Question

You are a meteorologist. While taking present weather observations, you note that the sky is full of wispy cirrus clouds estimated to be about 8 kilometers (km) overhead. If a warm front is approaching from the south, has a slope of 1:300 and is moving toward you at an average warm-front speed of about 40 km/hour, it will it take -------hours to pass your area?

Answer 1

Answer:

It will take 60 hours to pass your area

Explanation:

From the question we are told that

         The the distance of wispy cirrus clouds is $d_w =6km = 6*10^3 m$

         The slope is given as $S = 1:300 = \frac{1}{300}$

          The speed is $v = 40km/hour$

Since the slope is 1:300 which indicates the change in  the distance of the wispy cirrus clouds overhead to the distance of the warm front

   Now  if

             1 km → 300 km

Then

              $8km$ → x km  

Cross multiplying  and making x the subject

            $x = 8 *300 = 2400 \ km$

 Velocity is mathematically denoted as

                  $velocity(v) = \frac{Distance(d) }{Time(t) }$

Now making time the subject

                  $Time (t) = \frac{Distance }{Velocity}$

Now substituting values we have

                  $t =\frac{2400}{40}$

                     $= 60\ hours$