All categories

4 years ago

Who was the Governor of Anchorage, Alaska?

Physics

2 answers:

quester [9]4 years ago

5 0

I believe your talking about Bill Walker. :-)<span />

OLga [1]4 years ago

4 0

Bill Walker is the current Governor of Anchorage, Alaska

You might be interested in

Two identical objects in outer space have a head-on collision and stick together. If, before the collision, one had been moving

julia-pushkina [17]

Answer:

1.5 m/s

Explanation:

Momentum is conserved and conservation of momentum is

p₁ + p₂ = p'₁ + p'₂

m₁v₁ + m₂v₂ = m₁v'₁ + m₂v'₂

In our problem, after collision v'₁ will be equal to v'₂.

Since objects are identical m₁ = m₂

m(v₁+ v₂) = 2m x v'₁

(2m/s + 1m/s) = 2v'₁

v'₁ = v'₂ = 1.5 m/s

5 0

3 years ago

A calorimeter uses the temperature change of water to determine the _____ of another substance.

Evgesh-ka [11]

Answer:

A calorimeter uses the temperature change of water to determine the <u>specific heat </u> of another substance.

Explanation:

8 0

3 years ago

Recall the thermal energy model you used earlier to simulate friction with the chemistry and physics books. How does heat travel

dsp73

Answer:

due to condection of heat from pan in thermal energy according to 9th

Explanation:

7 0

3 years ago

Read 2 more answers

PLEASE HELP ME ASAP!!!!!!! <br> giving brainliest for correct answers

Vera_Pavlovna [14]

Answer:

Explanation:

6 0

3 years ago

A constant force of 45 N directed at angle θ to the horizontal pulls a crate of weight 100 N from one end of a room to another a

Rasek [7]

Answer:

$W=173.48J$

Explanation:

information we know:

Total force: $F=45N$

Weight: $w=100N$

distance: $4m$

vertical component of the force: $F_{y}=12N$

-------------

In this case we need the formulas to calculate the components of the force (because to calculate the work we need the horizontal component of the force).

horizontal component: $F_{x}=Fcos\theta$

vertical component: $F_{y}=Fsen\theta$

but from the given information we know that $F_{y}=12N$

so, equation these two $F_{y}=Fsen\theta$ and $F_{y}=12N$

$Fsen\theta =12N$

and we know the force $F=45N$ , thus:

$45sen\theta=12$

now we clear for $\theta$

$sen\theta =12/45\\\theta=sin^{-1}(12/45)\\\theta =15.466$

the angle to the horizontal is 15.466°, with this information we can calculate the horizontal component of the force:

$F_{x}=Fcos\theta$

$F_{x}=45cos(15.466)\\F_{x}=43.37N$

whith this horizontal component we calculate the work to move the crate a distance of 4 m:

$W=F_{x}*D\\W=(43.37N)(4m)\\W=173.48J$

the work done is W=173.48J

7 0

3 years ago