OMG ITS B ITS B I HOPE I HELPED U
Answer:
The kinetic energy is ![KE = 7.59 *10^{10} \ J](https://tex.z-dn.net/?f=KE%20%20%3D%20%207.59%20%20%2A10%5E%7B10%7D%20%5C%20%20J)
Explanation:
From the question we are told that
The radius of the orbit is ![r = 2.3 *10^{4} \ km = 2.3 *10^{7} \ m](https://tex.z-dn.net/?f=r%20%3D%20%202.3%20%2A10%5E%7B4%7D%20%5C%20km%20%20%3D%202.3%20%20%2A10%5E%7B7%7D%20%5C%20m)
The gravitational force is ![F_g = 6600 \ N](https://tex.z-dn.net/?f=F_g%20%20%3D%206600%20%5C%20N)
The kinetic energy of the satellite is mathematically represented as
![KE = \frac{1}{2} * mv^2](https://tex.z-dn.net/?f=KE%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20mv%5E2)
where v is the speed of the satellite which is mathematically represented as
![v = \sqrt{\frac{G M}{r^2} }](https://tex.z-dn.net/?f=v%20%20%3D%20%5Csqrt%7B%5Cfrac%7BG%20%20M%7D%7Br%5E2%7D%20%7D)
=> ![v^2 = \frac{GM }{r}](https://tex.z-dn.net/?f=v%5E2%20%20%3D%20%20%5Cfrac%7BGM%20%7D%7Br%7D)
substituting this into the equation
![KE = \frac{ 1}{2} *\frac{GMm}{r}](https://tex.z-dn.net/?f=KE%20%20%3D%20%20%5Cfrac%7B%201%7D%7B2%7D%20%2A%5Cfrac%7BGMm%7D%7Br%7D)
Now the gravitational force of the planet is mathematically represented as
![F_g = \frac{GMm}{r^2}](https://tex.z-dn.net/?f=F_g%20%20%3D%20%5Cfrac%7BGMm%7D%7Br%5E2%7D)
Where M is the mass of the planet and m is the mass of the satellite
Now looking at the formula for KE we see that we can represent it as
![KE = \frac{ 1}{2} *[\frac{GMm}{r^2}] * r](https://tex.z-dn.net/?f=KE%20%20%3D%20%20%5Cfrac%7B%201%7D%7B2%7D%20%2A%5B%5Cfrac%7BGMm%7D%7Br%5E2%7D%5D%20%2A%20r)
=> ![KE = \frac{ 1}{2} *F_g * r](https://tex.z-dn.net/?f=KE%20%20%3D%20%20%5Cfrac%7B%201%7D%7B2%7D%20%2AF_g%20%2A%20r)
substituting values
![KE = \frac{ 1}{2} *6600 * 2.3*10^{7}](https://tex.z-dn.net/?f=KE%20%20%3D%20%20%5Cfrac%7B%201%7D%7B2%7D%20%2A6600%20%2A%202.3%2A10%5E%7B7%7D)
![KE = 7.59 *10^{10} \ J](https://tex.z-dn.net/?f=KE%20%20%3D%20%207.59%20%20%2A10%5E%7B10%7D%20%5C%20%20J)
Answer:
40m/s
Explanation:
The horizontal component of velocity remains constant because there are no external forces in that direction
By applying motion equations, V= U+ at
where ,
- v - final velocity
- u - initial velocity
- a-acceleration
- t - time
v = u +at
As no force act on the ball ( we neglect air resistance here) no acceleration is seen,
So v = u = 40m/s