2 years ago

Which statement is true?

Chemistry

1 answer:

Elena-2011 [213]2 years ago

4 0

The letter only has reflection symmetry, if you rotated it it would look the same.

You might be interested in

Choose the letter of the choice that best completes the statement or answers the question. Elements in the same group have the s

pav-90 [236]

Elements in the same group have D. Same number of valence electrons.

6 0

3 years ago

Read 2 more answers

Al + Fe2O3 → Al2O3 + Fe (Need to balance equation)

andriy [413]

20.7 g of Fe can be produced with 10.0g of Al

6 0

3 years ago

Please describe the relationship between these pairs of compound as: isomers, identical, or unrelated

RUDIKE [14]

A.) CIS/Trans isomers
b.) constitutional isomers
c.) identical
d.) constitutional isomers
e.) identical

4 0

3 years ago

A mixture contains NaHCO3 together with unreactive components. A 1.75 g sample of the mixture reacts with HA to produce 0.561 g

Lynna [10]

Answer:

$\%NaHCO_3=61.2\%$

Explanation:

Hello.

In this case, since the undergoing chemical reaction is only between the sodium bicarbonate and the acid HA:

$NaHCO_3+HA\rightarrow NaA+H_2O+CO_2$

For 0.561 g of yielded carbon dioxide (molar mass 44 g/mol), the following mass of sodium bicarbonate (molar mass 84 g/mol) that reacted was:

$m_{NaHCO_3}=0.561gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molNaHCO_3}{1molCO_2} *\frac{84gNaHCO_3}{1molNaHCO_3} \\\\m_{NaHCO_3}=1.071g$

Considering the 1:1 mole ratio between CO2 and NaHCO3. Finally, the percent by mass of NaHCO3 is computed by dividing the mass of reacted NaHCO3 and t the mixture:

$\%NaHCO_3=\frac{1.071g}{1.75g}*100\%\\ \\\%NaHCO_3=61.2\%$

Best regards.

5 0

3 years ago

Why do crisp packets become inflated at high altitudes? Again, explain in as great a detail as possible, using ideas about parti

Andrei [34K]

As you get higher the atmospheric pressure lowers. The pressure in the packet of crisps has the pressure at which it has been closed (pressure at the surface of the earth). This means that the air molecules in the packet press harder outside than the air molecules in the atmosphere press on the packet.

3 0

3 years ago