1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brrunno [24]
3 years ago
6

water jet leaves a horizontal nozzle with a velocity of 12 m/s and mass flow rate of 30 kg/sstrikes the vertical wall of a cart

moving at a fixed direction. After the strike, the water splatters ofin all directions on the surface of the cart wall. Determine the force which must be applied to thecart to: (a) keep it moving at a constant velocity of 4 m/s, (b) to keep it motionless at a fixed posi-tion. Assume that the density of water is 1000 kg/m3.
Physics
1 answer:
amid [387]3 years ago
4 0

Answer:

a) 160 N

b) 360 N

Explanation:

v = 12 m/s

\dot{m} = 30 kg/s

ρ = 1000 kg/m^3

a) when the water  jet is moving at a constant velocity, then force exerted by the jet in the moving plane,

Fx = ρA(v- 4)^2

\dot{m} =ρAv

30 = 1000*A*12

A=2.5*10^(-3)

Fx = ρA(v-4)

Fx = 1000*2.5*10^(-3)*(12 - 4)^2

Fx = 160 N

b) When water jet striking on a stationary vertical plate, the force in the direction of jet:

Fx = ρAv^2

Fx = 1000*2.5*10^(-3)*12^2

Fx = 360 N

You might be interested in
Can someone please explain the quantum theory in simple terms
BaLLatris [955]
Quantum theory is the theoretical basis of modern physics that explains the nature and behavior of matter and energy on the atomic and subatomic level. The nature and behavior of matter and energy at that level is sometimes referred to as quantum physics and quantum mechanics.
6 0
3 years ago
Which process is responsible for changing the composition of rock?
Crazy boy [7]

Erosion, weathering, mechanical changes, chemical changes.

Really, any interaction can change the composition of a rock whether it be done by man or through nature.

4 0
3 years ago
Read 2 more answers
What is the speed shown in the graph? which number do i start on?
den301095 [7]

Answer:

4 m/s

Explanation:

speed = distance/time

speed= 20/5 = 4

similarly for all no. the answer is constant,i.e. 4

3 0
3 years ago
Planet 1 orbits Star 1 and Planet 2 orbits Star 2 in circular orbits of the same radius. However, the orbital period of Planet 1
hichkok12 [17]

Answer:

The mass of Star 2 is Greater than the mass of Start 1. (This, if we suppose the masses of the planets are much smaller than the masses of the stars)

Explanation:

First of all, let's draw a free body diagram of a planet orbiting a star. (See attached picture).

From the free body diagram we can build an equation with the sum of forces between the start and the planet.

\sum F=ma

We know that the force between two bodies due to gravity is given by the following equation:

F_{g} = G\frac{m_{1}m_{2}}{r^{2}}

in this case we will call:

M= mass of the star

m= mass of the planet

r = distance between the star and the planet

G= constant of gravitation.

so:

F_{g} =G\frac{Mm}{r^{2}}

Also, if the planet describes a circular orbit, the centripetal force is given by the following equation:

F_{c}=ma_{c}

where the centripetal acceleration is given by:

a_{c}=\omega ^{2}r

where

\omega = \frac{2\pi}{T}

Where T is the period, and \omega is the angular speed of the planet, so:

a_{c} = ( \frac{2\pi}{T})^{2}r

or:

a_{c}=\frac{4\pi^{2}r}{T^{2}}

so:

F_{c}=m(\frac{4\pi^{2}r}{T^{2}})

so now we can do the sum of forces:

\sum F=ma

F_{g}=ma_{c}

G\frac{Mm}{r^{2}}=m(\frac{4\pi^{2}r}{T^{2}})

in this case we can get rid of the mass of the planet, so we get:

G\frac{M}{r^{2}}=(\frac{4\pi^{2}r}{T^{2}})

we can now solve this for T^{2} so we get:

T^{2} = \frac{4\pi ^{2}r^{3}}{GM}

We could take the square root to both sides of the equation but that would not be necessary. Now, the problem tells us that the period of planet 1 is longer than the period of planet 2, so we can build the following inequality:

T_{1}^{2}>T_{2}^{2}

So let's see what's going on there, we'll call:

M_{1}= mass of Star 1

M_{2}= mass of Star 2

So:

\frac{4\pi^{2}r^{3}}{GM_{1}}>\frac{4\pi^{2}r^{3}}{GM_{2}}

we can get rid of all the constants so we end up with:

\frac{1}{M_{1}}>\frac{1}{M_{2}}

and let's flip the inequality, so we get:

M_{2}>M_{1}

This means that for the period of planet 1 to be longer than the period of planet 2, we need the mass of star 2 to be greater than the mass of star 1. This makes sense because the greater the mass of the star is, the greater the force it applies on the planet is. The greater the force, the faster the planet should go so it stays in orbit. The faster the planet moves, the smaller the period is. In this case, planet 2 is moving faster, therefore it's period is shorter.

6 0
3 years ago
What are two reasons why a home computer scanner requires
alexandr1967 [171]

Answer: C and D

Explanation: a p e x

4 0
3 years ago
Read 2 more answers
Other questions:
  • When you double the distance between a pair of charged particles what happens to the force between them?
    5·1 answer
  • You are a working for a rail company and are studying the effects of rain on open train cars. As a test case, you consider a 6,3
    8·1 answer
  • Question 11(Multiple Choice Worth 3 points)
    12·1 answer
  • A point charge q = +4.50 nC moves through a potential difference ΔV = Vf − Vi = +27.0 V. What is the change in the electric pote
    10·1 answer
  • At the instant the traffic light turns green, a car starts with a const acceleration of 7.00 ft/sA2. At the same instant a truck
    6·1 answer
  • A group of particles of total mass 35 kg has a total kinetic energy of 313 J. The kinetic energy relative to the center of mass
    7·1 answer
  • A mass of 0.8 kg is fixed at a vertical spring with an unknown spring constant. When spring is released from rest, it extends to
    9·1 answer
  • I'm not quite sure how the formula works. I thought it was
    8·1 answer
  • Please help me:)
    9·1 answer
  • Which element forms more com-<br> pounds than all the other elements<br> combined?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!