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Andrew [12]
3 years ago
8

Question 6

Physics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

B: Process #1: Energy is decreasing Process#2: Energy is increasing

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To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
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Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

We know that:

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So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

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Finally, the change in temperature of an object is related to the energy supplied by

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where in this problem:

E = 3276 J is the energy supplied

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Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

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Explanation:

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