Answer:
Explanation:
Given that,
Height of the bridge is 20m
Initial before he throws the rock
The height is hi = 20 m
Then, final height hitting the water
hf = 0 m
Initial speed the rock is throw
Vi = 15m/s
The final speed at which the rock hits the water
Vf = 24.8 m/s
Using conservation of energy given by the question hint
Ki + Ui = Kf + Uf
Where
Ki is initial kinetic energy
Ui is initial potential energy
Kf is final kinetic energy
Uf is final potential energy
Then,
Ki + Ui = Kf + Uf
Where
Ei = Ki + Ui
Where Ei is initial energy
Ei = ½mVi² + m•g•hi
Ei = ½m × 15² + m × 9.8 × 20
Ei = 112.5m + 196m
Ei = 308.5m J
Now,
Ef = Kf + Uf
Ef = ½mVf² + m•g•hf
Ef = ½m × 24.8² + m × 9.8 × 0
Ef = 307.52m + 0
Ef = 307.52m J
Since Ef ≈ Ei, then the rock thrown from the tip of a bridge is independent of the direction of throw
Answer:
b. varies inversely with the square of the distance from the center of Earth.
Explanation:
Comparing the Newton's law of universal gravitation and second law of motion;
from Newton's second law of motion,
F = ma ............. 1
from New ton's law of universal gravitation,
F = 
........... 2
Equating 1 and 2, we have;
mg =
g = 
Therefore, the acceleration due to gravity near Earth, g, is inversely proportional to the square of the distance from the center of Earth.
Answer:
A: ≤ means less than OR equal to. < only means less than
B: 9
Explanation:
A: Because it would equal 19, and 19 is EQUAL than 19. 4(5) - 1 would equal 19, which is equal to 19, and not less than. ≤ means less than or equal to. < means less than. So its not true.
B: 47 - 2, 45. Then 5 x 9 equals 45. So 5 x 9 equals 45, then add 2 would equal 47.
Hope this helps <3
2m/s^2, this is because F=ma, meaning a is also equal to F/m. The car applies 1500N in one direction and outside sources apply a total of -500N, meaning the 500kg car is moving forward with a total of 1000N of force. Taking the total 1000N and dividing it by 500kg gives you and acceleration of 2m/s^2. Hope this helps!
Answer:
The value is 
Explanation:
From the question we are told that
The diameter of the pupil is 
The distance of the page from the eye 
The wavelength is 
The refractive index is 
Generally the minimum separation of adjacent dots that can be resolved is mathematically represented as
![y = [ \frac{1.22 * \lambda }{d_p * n_r } ]* d](https://tex.z-dn.net/?f=y%20%20%3D%20%5B%20%5Cfrac%7B1.22%20%2A%20%20%5Clambda%20%7D%7Bd_p%20%2A%20n_r%20%7D%20%5D%2A%20d)
![y = [ \frac{1.22 * 500 *10^{-9} }{4.2 *10^{-3} * 1.36} ]* 0.29](https://tex.z-dn.net/?f=y%20%20%3D%20%5B%20%5Cfrac%7B1.22%20%2A%20%20500%20%2A10%5E%7B-9%7D%20%7D%7B4.2%20%2A10%5E%7B-3%7D%20%2A%201.36%7D%20%5D%2A%200.29)
