1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nirvana33 [79]
3 years ago
5

Please write the command(s) you should use to achieve the following tasks in GDB. 1. Show the value of variable "test" in hex fo

rmat. 2. Show the top four bytes on your stack word-by-word, e.g. it should look something like this "0x0102 0x0304", NOT "0x01020304". 3. Check all register values. 4. Set a breakpoint at "ece.c" line 391
Engineering
1 answer:
tester [92]3 years ago
7 0

Answer:

Explanation:

(gdb) n

539         len_rquote = strlen(lquote);

(gdb) n

540     }

(gdb) p len_lquote

$3 = 9

(gdb) p len_rquote

$4 = 7

You might be interested in
Assume you are an observer standing at a point along a three-lane roadway. All vehicles in lane 1 are traveling at 30 mi/h, all
garik1379 [7]

Answer:

Explanation:

Given data;

  • In line 1, v1 = 30mi/hr
  • in line 2, v2 = 45mi/hr
  • in line 3, v3 = 60mi/hr
  • therefore time mean speed = v1 + v2 + v3 /n
  • = VT = 45mi/hr

  • space mean speed ; Vs
  • harmonic mean = 1/V = 1/v1 + 1/v2 + 1/v3
  • V = 13.85mi/hr
  • Hence Vs = V x n = 3 x 13.85 = 41.55mi/hr
5 0
3 years ago
I will definitely rate 5 stars/brainliest!!! HELP PLEASE!!! State University must purchase 1,100 computers from three vendors. V
romanna [79]
Why 1+12+ Y3 < 1100
Says the state of university Need to purchase 1100 computers in total, we have the following answer on the way top
3 0
3 years ago
Two gage marks are placed exactly 250 mm apart on a 12-mm-diameter aluminum rod with E 5 73 GPa and an ultimate strength of 140
NNADVOKAT [17]

Answer:

81.76 N/mm² ( MPa), 1.71233

Explanation:

Modulus of elasticity = stress / strain

stress = modulus of elastic × strain

strain = ΔL / L = 250.28 mm - 250 mm / 250 mm = 0.00112

Modulus of elasticity E = 73 GPa = 73 × 10³ MPa where 1 MPa = 1 N/mm²

E = 73 × 10³N/mm²

stress =  73 × 10³N/mm²× 0.00112 = 81.76 N/mm² ( MPa)

b) Factor of safety = maximum allowable stress / induced stress = 140 MPa / 81.76 MPa = 1.71233

8 0
4 years ago
A thick aluminum block initially at 26.5°C is subjected to constant heat flux of 4000 W/m2 by an electric resistance heater whos
Yanka [14]

Given Information:

Initial temperature of aluminum block = 26.5°C

Heat flux = 4000 w/m²

Time = 2112 seconds

Time = 30 minutes = 30*60 = 1800 seconds

Required Information:

Rise in surface temperature = ?

Answer:

Rise in surface temperature = 8.6 °C after 2112 seconds

Rise in surface temperature = 8 °C after 30 minutes

Explanation:

The surface temperature of the aluminum block is given by

T_{surface} = T_{initial} + \frac{q}{k} \sqrt{\frac{4\alpha t}{\pi} }

Where q is the heat flux supplied to aluminum block, k is the conductivity of pure aluminum and α is the diffusivity of pure aluminum.

After t = 2112 sec:

T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (2112)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.51098)\\\\T_{surface} = 26.5 + 8.6\\\\T_{surface} = 35.1\\\\

The rise in the surface temperature is

Rise = 35.1 - 26.5 = 8.6 °C

Therefore, the surface temperature of the block will rise by 8.6 °C after 2112 seconds.

After t = 30 mins:

T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (1800)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.4717)\\\\T_{surface} = 26.5 + 7.96\\\\T_{surface} = 34.5\\\\

The rise in the surface temperature is

Rise = 34.5 - 26.5 = 8 °C

Therefore, the surface temperature of the block will rise by 8 °C after 30 minutes.

5 0
3 years ago
A certain power-supply filter produces an output with a ripple of 100 mV peak-to-peak and a dc value of 20 V. The ripple factor
Oksanka [162]

Answer: the ripple factor is 0.005

Explanation:

Given the data in the question;

we know that expression of ripple factor is;

r = Vr(pp) / Vdc

where Vr(pp) the peak to peak is ripple voltage ( 100mv = 0.1 V)

and Vdc is the dc value of the filter output voltage ( 20 V)

so we substitute our given values;

r = 0.1 / 20

r = 0.005

Therefore; the ripple factor is 0.005

8 0
3 years ago
Other questions:
  • In RSA Digital Signature, Suppose Bob wants to send a signed message (x = 4) to Alice. The first steps are exactly t eps are exa
    5·1 answer
  • Complete the following sentence.
    7·1 answer
  • potential difference is the work done in moving a unit positive charge from one point to another in an electric field. State Tru
    12·1 answer
  • In no less than one hundred fifty words, explain how microstructures reduce friction within fluid power systems. Mention some of
    8·1 answer
  • Compressed Air In a piston-cylinder device, 10 gr of air is compressed isentropically. The air is initially at 27 °C and 110 kPa
    11·1 answer
  • Visual aids are useful for all of the following reasons except
    11·1 answer
  • Deidre has just moved from the sales department into the finance department. On her first day in her new role, she receives an e
    14·1 answer
  • 2. How many amperes of current will flow through a circuit that has 3 ohms of resistance if
    5·1 answer
  • 1.The HCF of 15 and 20?<br>2.5!=??...????​
    9·2 answers
  • The only difference between all GMA welding machines and some FCA welding machines is that all GMA welding machines must have a
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!