Question

Suppose that tank holds 1% liquid water by volume and 99% vapor water by volume at a temperature of 185oC. What is the quality?

Answer 1

Answer:

quantity = 0.645749

Explanation:

given data

holds liquid water = 1%

hold vapor water  = 99%

temperature =  185°C

solution

we know that at temperature 185°C

Specific Volume of Saturated Liquid water (vf) = 0.0011343 m³/kg

and Specific Volume of Saturated Vapor (vg) = 0.17390 m³/kg

so quality will be

quality = $\frac{vapour*specific\ volume\ water}{water*specific\ volume\ vapour}$    ................1

put here value we get

quality = $\frac{99*0.0011343}{1*0.17390}$

quantity = 0.645749