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Free_Kalibri [48]
3 years ago
10

Suppose that tank holds 1% liquid water by volume and 99% vapor water by volume at a temperature of 185oC. What is the quality?

Engineering
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

quantity = 0.645749

Explanation:

given data

holds liquid water = 1%

hold vapor water  = 99%

temperature =  185°C

solution

we know that at temperature 185°C

Specific Volume of Saturated Liquid water (vf) = 0.0011343 m³/kg

and Specific Volume of Saturated Vapor (vg) = 0.17390 m³/kg

so quality will be

quality = \frac{vapour*specific\ volume\ water}{water*specific\ volume\ vapour}    ................1

put here value we get

quality = \frac{99*0.0011343}{1*0.17390}

quantity = 0.645749

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Explanation:

A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor

A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor

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