Suppose that tank holds 1% liquid water by volume and 99% vapor water by volume at a temperature of 185oC. What is the quality?
1 answer:
Answer:
quantity = 0.645749
Explanation:
given data
holds liquid water = 1%
hold vapor water = 99%
temperature = 185°C
solution
we know that at temperature 185°C
Specific Volume of Saturated Liquid water (vf) = 0.0011343 m³/kg
and Specific Volume of Saturated Vapor (vg) = 0.17390 m³/kg
so quality will be
quality = ................1
put here value we get
quality =
quantity = 0.645749
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Answer:
a) the amount of energy produced in kJ/K is 0.73145 kJ/K
b) the amount of energy produced in kJ/K is 0.68975 kJ/K
The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.
Explanation:
Draw the T-s diagram.
a)
= 0.939 kJ/kg.K , m = 5 kg , T₂ = 520 K , T₁ = 280
R = [8.314 kJ / 44.01 kg.K] , P₂ = 20 bar , P₁ = 2 bar
Δs =
Substitute all parameters in the equation
Δs =
Δs = 5 kg × 0.14629 kJ/kg.K
= 0.73145 kJ/K
b)
Δs =
Where T₁ = 280 K , s°(T₁) = 211.376 kJ/kmol.K
T₂ = 520 K , s°(T₂) = 236.575 kJ/kmol.K
R = [8.314 kJ / 44.01 kg.K] , M = 44.01 kg.K , P₂ = 20 bar , P₁ = 2 bar
Δs =
= 5 kg (0.13795 kJ/kg.K)
= 0.68975 kJ/K
The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.
Answer:
0.2 m/s
Explanation:
The velocity of a point on the edge of a disk rotating disk can be calculated as:
Where is the angular velocity and r the radius of the disk. This leads to: