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vekshin1
3 years ago
14

Estudio de caso Teorema de Bayes. Las historias de casos clínicos indican que diversas enfermedades producen sistemas similares.

Suponga que un conjunto particular de síntomas, que se denotarán como evento M, ocurre solo cuando se presenta cualquiera de tres enfermedades, A, B o C, (Para mayor simplicidad, supondremos que las enfermedades A, B y C son mutuamente excluyentes). Estudios realizados demuestran estas probabilidades de adquirir las tres enfermedades: P(A) = 0,02 P(B) = 0,03 P(C) = 0,4 Las probabilidades de desarrollar los síntomas M, dada una enfermedad especifica, son: P(M|A)=0,80 P(M|B)=0,97 P(M|C)=0,60 Suponiendo que una persona enferma presente los síntomas M. ¿Cuál es la probabilidad de que la persona tenga la enfermedad A?
Engineering
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:  A

Explanation: Case study Bayes theorem. Case histories indicate that various diseases produce similar systems. Assume that a particular set of symptoms, which will be denoted as event M, occurs only when any of three diseases, A, B or C, occurs (For simplicity, we will assume that diseases A, B and C are mutually exclusive). Studies show these probabilities of acquiring the three diseases: P (A) = 0.02 P (B) = 0.03 P (C) = 0.4 The probabilities of developing M symptoms, given a specific disease, are: P (M | A) = 0.80 P (M | B) = 0.97 P (M | C) = 0.60 Assuming that a sick person has symptoms M. What is the probability that the person has disease A?

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Pie charts should have no more than eight segments. True or False?
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Pie charts generally should have no more than eight segments.

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Which bulb has the lowest total cost of operation? (a) Incandescent (b) Fluorescent (c) LED
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Answer: LED have the lowest cost of operation.

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If we ignore the initial procurement cost of the items the operational cost of any device consuming electricity is given by

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Among the three item's LED consumes the lowest power to give the same level of brightness as compared to the other 2 item's thus LED's shall have the lowest operational cost.

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3 years ago
You are about to perform PMCS on your M1114? What resource should you use for the procedures and instructions for performing PMC
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The resources and instructions that should be used for the procedures of performing PMCS are:

  1. Operator's manuals
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<h3>What is PMCS?</h3>

PMCS is an acronym for preventive maintenance checks and services and it can be defined as the maintenance, checks, and services that are typically performed before, during, and after the use of any type of military equipment such as:

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4 0
1 year ago
(3) Calculate the heat flux through a sheet of brass 7.5 mm (0.30 in.) thick if the temperatures at the two faces are 150°Cand 5
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a.) 1.453MW/m2,  b.)  2,477,933.33 BTU/hr  c.) 22,733.33 BTU/hr  d.) 1,238,966.67 BTU/hr

Explanation:

Heat flux is the rate at which thermal (heat) energy is transferred per unit surface area. It is measured in W/m2

Heat transfer(loss or gain) is unit of energy per unit time. It is measured in W or BTU/hr

1W = 3.41 BTU/hr

Given parameters:

thickness, t = 7.5mm = 7.5/1000 = 0.0075m

Temperatures 150 C = 150 + 273 = 423 K

                        50 C = 50 + 273 = 323 K

Temperature difference, T = 423 - 323 = 100 K

We are assuming steady heat flow;

a.) Heat flux, Q" = kT/t

K= thermal conductivity of the material

The thermal conductivity of brass, k = 109.0 W/m.K

Heat flux, Q" = \frac{109 * 100}{0.0075} = 1,453,333.33 W/m^{2} \\ Heat flux, Q" = 1.453MW/m^{2} \\

b.) Area of sheet, A = 0.5m2

Heat loss, Q = kAT/t

Heat loss, Q = \frac{109*0.5*100}{0.0075} = 726,666.667W

Heat loss, Q = 726,666.667 * 3.41 = 2,477,933.33 BTU/hr

c.) Material is now given as soda lime glass.

Thermal conductivity of soda lime glass, k is approximately 1W/m.K

Heat loss, Q=\frac{1*0.5*100}{0.0075} = 6,666.67W

Heat loss, Q = 6,666.67 * 3.41 = 22,733.33 BTU/hr

d.) Thickness, t is given as 15mm = 15/1000 = 0.015m

Heat loss, Q=\frac{109*0.5*100}{0.015} =363,333.33W

Heat loss, Q = 363,333.33 * 3.41 = 1,238,966.67 BTU/hr

5 0
3 years ago
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