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zhenek [66]
3 years ago
8

The annual interest on an $20,000 investment exceeds the interest earned on a $4000 investment by $1320. The $20,000 is invested

at a 0.6% higher rate of interest than the $4000. What is the interest rate of each investment?$20,000 is invested at what %$4,000 is invested at what %
Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Answer:

"8.8%"

Step-by-step explanation:

Let x be the interest rate for the 20,000 and y for the 4,000

The problem says:

x20,000 = y4,000+1320 (1)

and

x = y+0.006 Substitute this value for x on equation (1)

(y+0.006)20,000 = y4,000+1320

20,000y+120 = y4,000+1320

16,000y = 1320

y = 0.0825 So the 4,000 are invested at 8.25%

And since x = y+0.006:

x = .0825+0.006 = 0.0885 or 8.8%. The 20,000 are invested at 8.8%

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we need to get your brain thinking in this way. that you begin to understand how to do these things.

airways to say that your brain is not working that way, is not a valid excuse. we need to change that. your brain needs to get used to this way of thinking.

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1. as x increases, y decreases. until, suddenly after x=0, this tendency reverses, and with increasing x also y increases. so, this is a turning point.

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