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Arte-miy333 [17]
3 years ago
8

A 400 gram sample of alcohol at 10o C [Ca=2.64 J/g*oC] is mixed with 400 grams of warm water [Cw=4.186 J/g*Co] at 88o C. Assume

no heat is lost to the surroundings, what is the final temperature of the mixture when thermal equilibrium is reached?
Alcohol = -[Warm Water]
mCaΔT = -[mCwΔT]
can u help pls?
Physics
1 answer:
alukav5142 [94]3 years ago
8 0
The heat lost by the water will be equivalent to the energy gained by the alcohol. Thus:
maCaΔT = -mwCwΔT
400 x 2.64 x (T - 10) = 400 x 4.186 x (88 - T)
T = 57.8 °C
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Answer:

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Here in each swing the distance sweeps by the swing is half of the initial distance that it will move

So here we can say that total distance in whole motion is  given as

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6 0
3 years ago
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Svet_ta [14]

Answer:

See below ~

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Maximum mass of sand will be 1331 g. [because 1331/1331 = 1 g/cm³]

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If the volume of sand is <u>greater than 380.29 cm³</u>, the box will sink in water.

6 0
2 years ago
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BigorU [14]

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