Answer:
Explanation:
The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.
C2H4 + HBr ------------------------> C2H5Br.
The chemical species/compounds reacted in the ratio of 1 : 1 : 1. That is one mole of C2H4 reacted with one mole of HBr to give one mole of C2H5Br.
So, we are given; C2H5Br = 58.7 mol%, HBr = 18.3 mol%. Thus, for C2H4, we have [ 100 - (58.7 + 18.3)] = 23 mol%. Therefore, the limiting reagent is HBr.
So, if we have 100 mol/s ;
C2H5Br = 100 × 0.587 = 58.7 mol/s, HBr = 100 × 0.183 = 18.3 mol/s and C2H4 = 100 × 0.23 = 23 mol/s.
Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .
So, 100/158.7 × 30.5 = 192.2.
Also the feed composition in HBr and C2H4 is;
HBr = 77/158.7 = 0.4852, C2H4 = 81.7/158.7 = 0.515.
Therefore, the number of HBr in feed and C2H4 in feed = 160m/s and 200m/s respectively (approx.)
Therefore, the fraction conversion is;
