Answer:
713mmHg
Explanation:
By using Dalton's law of partial pressure, the pressure outside the gas container is equal to the pressure inside it and this pressure equals the sum of the pressures of water and the gas.
i.e, P(total) = P(gas) + P(water)
P(gas) = P(total) - P(water)
P(gas) = 735 - 22
P(gas) = 713mmHg
2.5 x 10^24 molecules of C4H10
Answer:
12.5% is left
Explanation:If the half-life of a reaction is 6 days. What percentage of material is left after 18 days?
18 days/6 days = 3 half lives
each half life you lose half the material
in 3 half lives you have (1/2)x (1/2) x (1/2) =1/8
1/8 =0.125 so 12.5% is left
% yield = 74.35
<h3>Further explanation</h3>
Given
12 dm³ ethene = 12 L
18.4 g ethanol(actual)
Required
The percentage yield
Solution
Reaction
C₂H₄(g) + H₂O(g) ⇒ C₂H₅OH(g)
Assume at STP, 1 mol gas = 22.4 L
mol ethene :
= 12 L : 22.4 L
= 0.538
From equation, mol ratio C₂H₅OH : C₂H₄ = 1 : 1, so mol C₂H₅OH = 0.538
Mass Ethanol (MW=46 g/mol) ⇒ theoretical
= 0.538 x 46
= 24.748 g
% yield = (actual/theoretical) x 100%
% yield = (18.4/24.748) x 100%
% yield = 74.35
Answer:
The concentration of CH₃OH in equilibrium is [CH₃OH] = <em>2,8x10⁻¹ M</em>
Explanation:
For the equilibrium:
CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5
Thus:
14,5 =
In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:
14,5 =
Solving, the concentration of CH₃OH in equilibrium is:
<em>[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M</em>
I hope it helps!