Question

Starting from rest, the distance a freely-falling object will fall in 0.50 second is?

Answer 1

Answer:

1.23 m

Explanation:

The vertical distance covered by a free-falling object starting from rest in a time t is

$y=\frac{1}{2}gt^2$

where

g = 9.8 m/s^2 is the acceleration due to gravity

In this problem, we have

t = 0.50 s

So the distance covered is

$y=\frac{1}{2}(9.8 m/s^2)(0.50 s)^2=1.23 m$