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slamgirl [31]
3 years ago
15

Please help me I only have a few questions and need this turned in by the end of the day! In all of our simulations we left the

Coefficient of Friction set to 0. As a result, you should have noticed that the potential energy would transfer directly into kinetic energy as it went down the hill (and vice versa as it went up a hill.) Describe what trends you would expect to see if we included a Coefficient of Friction (in other words, added friction into the simulation).
Physics
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Answer: did you ever get the answer i need help too

Explanation:

jasenka [17]3 years ago
4 0

Answer:

In the absence of non-conservative forces that is friction, the mechanical energy remains conserved. The potential energy changes to kinetic energy as it goes down the hill. At the bottom of the hill

the entire potential energy transforms to kinetic energy. In the presence of dissipative forces like frictional forces, some of the energy is dissipated as heat. So, potential energy does not convert entirely to kinetic energy.

If coefficient of friction was included, the graph would not be straight line but a curved as at the bottom, the kinetic energy is not equal to the potential energy at the top of the hill.

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When compared to other types of waves, electromagnetic waves differ because they are
expeople1 [14]
They differ because they are transverse wave. That is their direction of travel is perpendicular to its vibrations.
7 0
2 years ago
Two planets have masses 2 x 10^23 kg and 5 x 10^22 kg, and the distance between them is 3 x 10^16 m. Calculate the gravitational
xxTIMURxx [149]

Explanation:

given,

mass of one planet (m1)=2*10^23 kg

mass of another planet (m2)=5*10^22kg

distance between them(d)=3*10^16m

gravitational constant(G)=6.67*10^-11Nm^2kg^-2

gravitational force between them(F)=?

we know,

F=Gm1m2/d^2

or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2

or, F=6.67*2*5*10^-11+23+22/3*3*10^32

or, F=66.7*10^34/9*10^32

or, F=7.41*10^34-32

•°• F=7.41*10^2

thus, the gravitational force between them is 7.14*10^2

3 0
2 years ago
The gravitational attraction between two objects increases if
JulijaS [17]

Answer:

they are closer!!

Explanation:

Hope this helped!! :D

8 0
3 years ago
Under what condition will a glass lens placed in a transparent medium becomes invisible??
Viktor [21]

Answer:

A lens placed in a transparent liquid becomes invisible because when refractive index of the material of the lens is equal to the refractive index of the liquid in which lens is placed under this condition no bending of light takes place when it travels from liquid to the lens, so both will start behaving like both are same things.

Explanation:

hope it helps :))

5 0
2 years ago
The machine in the figure is ideal and an effort force of
DENIUS [597]

Answer:

1.5 m

Explanation:

Let the distance from the box to the pivot be c.

Let the distance from the pivot to the effort be y.

From the question given above, the following data were obtained:

Effort force (Fₑ) = 7 N

Force of resistance (Fᵣ) = 14 N

Distance from the box to the pivot (c) = 0.75 m

Distance from the pivot to the effort (y) =?

Clockwise moment = Fₑ × y

Anticlock wise moment = Fᵣ × c

Clockwise moment = Anticlock wise moment

Fₑ × y = Fᵣ × c

7 × y = 14 × 0.75

7 × y = 10.5

Divide both side by 7

y = 10.5 / 7

y = 1.5 m

Therefore, the distance from the pivot to the effort is 1.5 m

5 0
2 years ago
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