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slamgirl [31]
3 years ago
15

Please help me I only have a few questions and need this turned in by the end of the day! In all of our simulations we left the

Coefficient of Friction set to 0. As a result, you should have noticed that the potential energy would transfer directly into kinetic energy as it went down the hill (and vice versa as it went up a hill.) Describe what trends you would expect to see if we included a Coefficient of Friction (in other words, added friction into the simulation).
Physics
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Answer: did you ever get the answer i need help too

Explanation:

jasenka [17]3 years ago
4 0

Answer:

In the absence of non-conservative forces that is friction, the mechanical energy remains conserved. The potential energy changes to kinetic energy as it goes down the hill. At the bottom of the hill

the entire potential energy transforms to kinetic energy. In the presence of dissipative forces like frictional forces, some of the energy is dissipated as heat. So, potential energy does not convert entirely to kinetic energy.

If coefficient of friction was included, the graph would not be straight line but a curved as at the bottom, the kinetic energy is not equal to the potential energy at the top of the hill.

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C. Slippery feel

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3 years ago
A sample of Bismuth-212 has a mass of 2.64 grams (g) after 121 seconds (s). What was the initial mass of the sample if Bismuth-2
uysha [10]
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In our problem, m(t)=2.64 g, t=121.0 s and t_{1/2}=60.5 s, so we can find the initial mass m_0:
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4 0
3 years ago
What is the equivalent resistance of a circuit that contains four 75.0 resistors connected in parallel with a 100.0 V battery?
zhannawk [14.2K]
To get the total resistance in a parallel circuit, you need to remember that unlike in a series, you do not just merely add the resistances. You need to get the reciprocal first of each resistance and add them together. 

\frac{1}{R_{T}} =  \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}... +\frac{1}{R_{n}}

After adding them, you will get the reciprocal again and then compute for the value. The problem says that there are 4 resistors in the circuit that have a resistance of 75.

\frac{1}{R_{T}} = \frac{1}{75}+\frac{1}{75}+\frac{1}{75}+\frac{1}{75}

Add up the numerator and copy the denominator:

\frac{1}{R_{T}} = \frac{4}{75}

Then get the reciprocal to get the total resistance:

R _{T} = \frac{75}{4}  = 18.75

The answer to your question then is A. 18.8.
5 0
3 years ago
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