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slamgirl [31]
3 years ago
15

Please help me I only have a few questions and need this turned in by the end of the day! In all of our simulations we left the

Coefficient of Friction set to 0. As a result, you should have noticed that the potential energy would transfer directly into kinetic energy as it went down the hill (and vice versa as it went up a hill.) Describe what trends you would expect to see if we included a Coefficient of Friction (in other words, added friction into the simulation).
Physics
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Answer: did you ever get the answer i need help too

Explanation:

jasenka [17]3 years ago
4 0

Answer:

In the absence of non-conservative forces that is friction, the mechanical energy remains conserved. The potential energy changes to kinetic energy as it goes down the hill. At the bottom of the hill

the entire potential energy transforms to kinetic energy. In the presence of dissipative forces like frictional forces, some of the energy is dissipated as heat. So, potential energy does not convert entirely to kinetic energy.

If coefficient of friction was included, the graph would not be straight line but a curved as at the bottom, the kinetic energy is not equal to the potential energy at the top of the hill.

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Write down the condition required for the thermonuclear fusion.​
storchak [24]

Explanation:

The temperature must be hot enough to allow the ions of deuterium and tritium to have enough kinetic energy to overcome the Coulomb barrier and fuse together. The ions must be confined with a high ion density to achieve a suitable fusion reaction rate.

7 0
2 years ago
Read 2 more answers
If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
sdas [7]
Data:
f_{2} = 42 Hz
n (Wave node)
V (Wave belly) 
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
f_{n} =  \frac{nV}{2L}

Wire 2 → 2º Harmonic → n = 2

f_{n} = \frac{nV}{2L}
f_{2} = \frac{2V}{2L} &#10;
2V =  f_{2} *2L
V =  \frac{ f_{2}*2L }{2}
V =  \frac{42*2L}{2}
V =  \frac{84L}{2}
V = 42L

Wire 1 → 1º Harmonic or Fundamental rope → n = 1


f_{n} = \frac{nV}{2L}
f_{1} = \frac{1V}{2L}
f_{1} =  \frac{V}{2L}

If, We have:
V = 42L
Soon:
f_{1} = \frac{V}{2L}
f_{1} = \frac{42L}{2L}
\boxed{f_{1} = 21 Hz}

Answer:

<span>The fundamental frequency of the string:
</span>21 Hz

7 0
3 years ago
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What is a relatively soft layer of upper mantle called?
brilliants [131]
The answer is asthenosphere

3 0
3 years ago
n a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kinetic
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Answer:

Explanation:

a ) starting from rest , so u = o and initial kinetic energy = 0 .

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Total kinetic energy at the base = 343 m  + 0 = 343 m .

b )

In this case initial kinetic energy = 1/2 m v²

= .5 x m x 2.5²

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Total kinetic energy at the base

= 3.125 m  + 343 m

= 346.125 m

c ) It is not surprising as energy gained due to gravitational force by the earth is enormous . So component of energy gained due to gravitational force far exceeds the initial kinetic energy . Still in a competitive event , the fractional initial kinetic energy may be the deciding factor .

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If a car is accelerating downhill under a net force of 3674 N, what force must the brakes exert to cause the car to have constan
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Answer:

Explanation:

hi

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2 years ago
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