Answer:
Analysis
Explanation:
Because you must Analysis each and every cold too find out which virus caused this.
It’s weird because Interpretation and Analysis have the meaning of examination
Answer:
False.
Explanation:
This explanation is the opposite of true testing - a term known as falsifiability. Falsifiability, when it relates to science, refers to how it should be possible to prove a hypothesis or theory wrong. Thus, the point of testing for falsifiability is to test in which condition is the theory wrong.
A term that might relate to the phrase ‘true testing’ used in the question would be testability. Which refers to the practice of testing a hypothesis or theory to see whether it is true or false.
1) In any collision the momentum is conserved
(2*m)*(vo) + (m)*(-2*vo) = (2*m)(v1') + (m)(v2')
candel all the m factors (because they appear in all the terms on both sides of the equation)
2(vo) - 2(vo) = 2(v1') + (v2') => 2(v1') + v(2') = 0 => (v2') = - 2(v1')
2) Elastic collision => conservation of energy
=> [1/2] (2*m) (vo)^2 + [1/2](m)*(2*vo)^2 = [1/2](2*m)(v1')^2 + [1/2](m)(v2')^2
cancel all the 1/2 and m factors =>
2(vo)^2 + 4(vo)^2 = 2(v1')^2 + (v2')^2 =>
4(vo)^2 = 2(v1')^2 + (v2')^2
now replace (v2') = -2(v1')
=> 4(vo)^2 = 2(v1')^2 + [-2(v1')]^2 = 2(v1')^2 + 4(v1')^2 = 6(v1')^2 =>
(v1')^2 = [4/6] (vo)^2 =>
(v1')^2 = [2/3] (vo)^2 =>
(v1') = [√(2/3)]*(vo)
Answer: (v1') = [√(2/3)]*(vo)
Answer:
<em>a. t = 2.02 s
</em>
<em>b. d = 20.2 m</em>
Explanation:
<u>Horizontal Motion
</u>
If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The time the object takes to hit the ground can be calculated as follows:
The time does not depend on the initial speed.
The range or maximum horizontal distance traveled by the object can be calculated by the equation:
The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.
a.
The time taken by the rock to reach the ground is:
t = 2.02 s
b.
The range is:
d = 20.2 m
Based on your question the answer to this is the following and i hope i answered you question correctly:
How much energy is transferred to her eardrums each second ?
-6.31
<span>
How fast would a 2.00 mg mosquito have to fly to have this much kinetic energy? </span>
-1.39*10^-5<span>
How fast a typical 2.0 mg mosquito would have to fly (in mm/s) to have an amount of energy delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?
-</span><span>3.5 joules</span>
