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amm1812
4 years ago
4

A cylindrical gaussian surface surrounds an infinite line of charge. the flux φe through the two flat ends of the cylinder is

Physics
1 answer:
Dominik [7]4 years ago
8 0
A Gaussian surface<span> (sometimes abbreviated as g.s.) is a </span>closed surface<span> in three-dimensional space through which the </span>flux<span> of a </span>vector field<span> is calculated; usually the </span>gravitational field<span>, the </span>electric<span> field, or </span>magnetic<span> field.</span>[1]<span> It is an arbitrary </span>closed surface S<span> = ∂</span>V<span> (the </span>boundary<span> of a 3-dimensional region </span>V) used in conjunction with Gauss's law for the corresponding field (Gauss's law<span>, </span>Gauss's law for magnetism<span>, or </span>Gauss's law for gravity<span>) by performing a </span>surface integral<span>, in order to calculate the total amount of the source quantity enclosed; e.g., amount of </span>gravitational mass<span> as the source of the gravitational field or amount of </span>electric charge<span> as the source of the electrostatic field, or vice versa: calculate the fields for the source distribution.</span>
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What is the word that goes with the definition “ a disturbance in space that causes a force”
irga5000 [103]

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Explanation:

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3 years ago
What do you need to make 100 minutes charges neutral
Maru [420]
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3 years ago
Vector a has a magnitude of 12.3 units and points due west. vector b points due north. what is the magnitude of b if a - b has a
algol [13]

The magnitude of vector b is 8.58 Unit.

Since both the vectors a and b are perpendicular to each other, so we can apply the Pythagoras theorem to calculate the magnitude of the vector b.

Applying the Pythagoras theorem

(a-b)^2=a^2+b^2

15^2=12.3^2-b^2

b=8.58 unit

Therefor the magnitude of the vector b is 8.58 unit.

8 0
3 years ago
An electric field of 280000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -
nordsb [41]
<h2>The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.</h2>

Explanation:

Electric field is the ratio of force and charge.

Electric field, E = 280000 N/C

Charge, q = -7.9 C

We have

                 E=\frac{F}{q}\\\\280000=\frac{F}{7.9}\\\\F=280000\times 7.9\\\\F=2.21\times 10^6N

The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.

4 0
4 years ago
Will give Brainliest!! Question attached.
ss7ja [257]

Answer:

im pretty sure it is 3.0 K

Explanation:

8 0
3 years ago
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