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3 years ago

Psychologists define stress as?

Physics

1 answer:

d1i1m1o1n [39]3 years ago

7 0

An event that that causes tension or a person’s perception of an event.

You might be interested in

What does it mean by the fact that the acceleration of a car is 5m/s square??

dalvyx [7]

Answer:

An acceleration of 5m/s^2 means that the velocity of a body is increasing by 5m/s per second in a certain direction

Explanation:

5 0

3 years ago

If an element has 20 protons and 20 neutrons in the nucleus of its atoms , what is the mass number of the atom?

Ilya [14]

Answer:

A=z+n

A=20+20

A=40

Explanation:

Not sure if I'm correct but I was taught that mass number is calculated by A=z+n where A is the mass number, z is the proton number and n is the number of neutrons.

8 0

3 years ago

A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th

Gnoma [55]

Answer:

91.84 m/s²

Explanation:

velocity, v = 600 m/s

acceleration, a = 4 g = 4 x 9.8 = 39.2 m/s^2

Let the radius of the loop is r.

he experiences a centripetal force.

centripetal acceleration,

a = v² / r

39.2 x r = 600 x 600

r = 3600 / 39.2

r = 91.84 m/s²

Thus, the radius of the loop is 91.84 m/s².

8 0

3 years ago

The hydraulic oil in a car lift has a density of 8.53 x 102 kg/m3. The weight of the input piston is negligible. The radii of th

navik [9.2K]

Answer:

(a) the input force is 36.56 N

(b) the input force is 37.49 N

Explanation:

Given;

density of hydraulic oil, ρ = 8.53 x 10² kg/m³

radius of plunger, r₁ = 0.135 m

radius of piston, r₂ = 5.43 x 10⁻³ m

Part (a) The input force needed to support 22600-N weight, when the bottom surfaces of the piston and plunger are at the same level;

$P =\frac{F}{A}$

Where;

P is pressure

F is force

A is circular area = πr²

$\frac{F_1}{A_1} =\frac{F_2}{A_2} \\\\F_2 = \frac{F_1*A_2}{A_1} =\frac{F_1* \pi r_2^2}{\pi r_1^2} = \frac{F_1* r_2^2}{ r_1^2} \\\\F_2 = \frac{22600*(5.43*10^{-3})^2 }{(0.135)^2}\\\\F_2 = 36.56 \ N$

Part (b) The input force needed to support 22600-N weight, when the bottom surface of the output plunger is 1.20 m above that of the input plunger

$P_2 = P_1 + \rho gh$

But, F = PA and A = πr²

$F_2 = F_1(\frac{A_2}{A_1} ) + \rho gh*A_2\\\\F_2 = F_1(\frac{r_2^2}{r_1^2} )+\rho gh(\pi r_2^2)\\\\F_2 = 22600(\frac{5.43*10^{-3}}{0.135})^2 \ + 853*9.8*1.2*\pi (5.43*10^{-3})^2\\\\F_2=36.56 + 0.93\\\\F_2 = 37.49 \ N$

4 0

3 years ago

9. Batman (mass=91 kg) jumps straight down from a bridge into a boat (mass=510 kg) in which a criminal is fleeing. The velocity

Ierofanga [76]

Answer:

V = 9.33 m/s

Explanation:

Given that,

Mass of the batsman, $m_1=91\ kg$

Mass of the boat, $m_2=510\ kg$

Initial speed of the boat, v = 11 m/s

Let V is the velocity of the boat after Batman lands in it. The net momentum of the system remains constant. Using the conservation of linear momentum to find it as :

$510\times 11=(91+510)V$

$V=\dfrac{510\times11}{(91+510)}$

V = 9.33 m/s

So, the velocity of the boat after Batman lands in it 9.33 m/s. Hence, this is the required solution.

5 0

3 years ago