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Lorico [155]
3 years ago
7

Sopranos can sing notes at very high frequencies—over 1000 Hz. When they sing such high notes, it can be difficult to understand

the words they are singing. Use the concepts of harmonics and formants to explain this.
Physics
1 answer:
STALIN [3.7K]3 years ago
3 0

Answer: High frequency= High harmonics= Different formants

Explanation:

We are given that sopranos can sing notes at very high frequencies.

Now, when they sing high notes it is difficult to understand their words.

According to the  concept of harmonics, it is the integer multiple of the fundamental frequency. And formants are the different frequencies which in turn give us different vocalizations.

Now, the frequency is over 1000 Hz this implies that the harmonics will be greater and in turn formants will be different. So, this is the reason it is difficult to understand the words of sopranos when they are singing at very high frequencies.

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Explanation:

It is given that,

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Velocity of tackler, u₁ = 3 m/s

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We need to find the mutual velocity immediately the collision. It is the case of inelastic collision such that,

v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}

v=\dfrac{120\ kg\times 3\ m/s+91\ kg\times (-7.5\ m/s)}{120\ kg+91\ kg}

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3 years ago
Your lab instructor has asked you to measure a spring constant using a dynamic method—letting it oscillate—rather than a sta
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Answer:

  k = 6,547 N / m

Explanation:

This laboratory experiment is a simple harmonic motion experiment, where the angular velocity of the oscillation is

         w = √ (k / m)

angular velocity and rel period are  related

         w = 2π / T

substitution

         T = 2π √(m / K)

in Experimental measurements give us the following data

  m (g)     A (cm)    t (s)   T (s)

  100        6.5         7.8    0.78

  150        5.5          9.8   0.98

   200      6.0        10.9    1.09

   250       3.5        12.4    1.24

we look for the period that is the time it takes to give a series of oscillations, the results are in the last column

        T = t / 10

To find the spring constant we linearize the equation

        T² = (4π²/K)    m

therefore we see that if we make a graph of T² against the mass, we obtain a line, whose slope is

         m ’= 4π² / k

where m’ is the slope

           k = 4π² / m'

the equation of the line of the attached graph is

       T² = 0.00603 m + 0.0183

therefore the slope

       m ’= 0.00603  s²/g

    we calculate

         k = 4 π² / 0.00603

          k = 6547 g / s²

we reduce the mass to the SI system

         k = 6547 g / s² (1kg / 1000 g)

         k = 6,547 kg / s² =

         k = 6,547 N / m

let's reduce the uniqueness

         [N / m] = [(kg m / s²) m] = [kg / s²]

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Answer:

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Mass of object 1 = MA

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Distance between them = x₁

U = -[(G)(MA)(MB)/x₁]

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