Answer: option E. None because in all the reactions O2 is in excess
Explanation:
Answer:
0.8 mL of protein solution, 9.2 mL of water
Explanation:
The dilution equation can be used to relate the concentration C₁ and volume V₁ of the stock/undiluted solution to the concentration C₂ and volume V₂ of the diluted solution:
C₁V₁ = C₂V₂
We would like to calculate the value for V₁, the volume of the inital solution that we need to dilute to make the required solution.
V₁ = (C₂V₂) / C₁ = (2mg/mL x 10mL) / (25 mg/mL) = 0.8 mL
Thus, a volume of 0.8 mL of protein solution should be diluted with enough water to bring the total volume to 10 mL. The amount of water needed is:
(10 mL - 0.8 mL) = 9.2 mL
<span>Which of the following are indicators of a chemical change? Select all that apply.
</span>
These are the answers:
<span>color change
temperature change
precipitate formation
gas formation
Hope this helps.
</span>
Answer:
Approximately
.
Explanation:
Make use of the molar mass data (
) to calculate the number of moles of molecules in that
of
:
.
Make sure that the equation for this reaction is balanced.
Coefficient of
in this equation:
.
Coefficient of
in this equation:
.
In other words, for every two moles of
that this reaction consumes, two moles of
would be produced.
Equivalently, for every mole of
that this reaction consumes, one mole of
would be produced.
Hence the ratio:
.
Apply this ratio to find the number of moles of
that this reaction would have produced:
.
3.47 x
atoms of gold have mass of 113.44 grams.
Explanation:
Data given:
number of atoms of gold = 3.47 x
mass of the gold in given number of atoms = ?
atomic mass of gold =196.96 grams/mole
Avagadro's number = 6.022 X 
from the relation,
1 mole of element contains 6.022 x
atoms.
so no of moles of gold given = 
0.57 moles of gold.
from the relation:
number of moles = 
rearranging the equation,
mass = number of moles x atomic mass
mass = 0.57 x 196.96
mass = 113.44 grams
thus, 3.47 x
atoms of gold have mass of 113.44 grams