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2 years ago

Explain how are elements classified and provide an example

Chemistry

1 answer:

swat322 years ago

4 0

By nonmetals, metals, and gases

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(a) How many moles of CO2 contain 2.42 ✕ 1024 molecules?

Vikki [24]

Don’t currently have a calculator with me but just use Avogadros constant (A) 6.02x10^24, in the equation n=N/A. Lower case n being the number of mol and upper case being the number of molecules (given).

4 0

2 years ago

Suppose that you take 200 mg of an antibiotic every 8 hr. The half-life of the drug is 8 hr (the time it takes for half of the

DochEvi [55]

Answer:

600 mg

Explanation:

The initial amount of the drug = 200 mg

The half-life of the drug = 8 hrs

It means that:-

After 6 hours, the concentration becomes :- $\frac{200}{2}$ mg

After 12 hours, the concentration becomes :- $\frac{200}{4}$ mg

After 18 hours, the concentration becomes :- $\frac{200}{8}$ mg

And so on...

Thus,

After infinite time = $200+\frac{200}{2}+\frac{200}{4}+\frac{200}{8}+..$

Thus,

After infinite time = $200\times (1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+..)$

The sum of the infinite series is:- $1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+..$ = $\frac{1}{1+\frac{1}{2}}=2$

So,

<u>After infinite time = $200\times 2$ mg = 600 mg</u>

5 0

3 years ago

What are atoms comprised of?

inessss [21]

Answer:

Protons, Neutrons, and Electrons

Explanation:

8 0

3 years ago

15. What volume of CCI, (d = 1.6 g/cc) contain

anastassius [24]

Answer:

$\boxed{\text{(3) 9.6 L}}$

Explanation:

1. Moles of CCl₄

$n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}$

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

$m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}$

4. Volume of CCl₄

$V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}$

4 0

2 years ago

URGENT!

tensa zangetsu [6.8K]

Answer:

Explanation:

A weak acid and a strong base will form a basic salt.

Option A is acidic, this pH would be found in salts formed from reactions between strong acids and weak bases.

B and C are neutral or close to neutral and as such will be formed from weak acids and weak bases, or strong acids and strong bases.

5 0

3 years ago

Read 2 more answers