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2 years ago

Explain how are elements classified and provide an example

Chemistry

1 answer:

swat322 years ago

4 0

By nonmetals, metals, and gases

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What is the % composition of Carbon in Chromium (iii) Carbonate

photoshop1234 [79]

Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):

$Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3$

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

$\begin{gathered} C\rightarrow3\times12=36 \\ \\ O\rightarrow9\times16=144 \\ \\ Cr\rightarrow2\times52=104 \end{gathered}$

The molar mass will be thus:

$M=36+104+144=284\text{ g/mol}$

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

$\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\ \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}$

The percent composition of Carbon is thus 12.7 %.

8 0

1 year ago

HELP ASAP

Bezzdna [24]

A. I think sorry if it’s wrong

5 0

2 years ago

Hey guys, about to submit my draft for business and chemistry.

drek231 [11]

Answer:

so u can put on hot sauce to spice it up

and give it to ur teacher

8 0

3 years ago

Read 2 more answers

Which element or elements are unbalanced in this equation?

Stells [14]

Answer:

Only the H is unbalanced.

Explanation:

There are 4 H's and 2 of everything else

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3 years ago

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If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa

Genrish500 [490]

If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

$v2/v1 = \sqrt{L2/L1}$

$v2/v1 = \sqrt{2}$

In conclusion,v ratio will give us

v=1.414 times