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goblinko [34]
3 years ago
11

Ball joints on a vehicle equipped with MacPherson struts are being inspected for wear. Which of the following would be the corre

ct method to check the load bearing joint?
Question 2 options:

Leave the vehicle weight on the tires, turn the steering wheel and listen for a popping noise.


Raise the vehicle by the subframe and measure the joints vertical movement.


Raise the vehicle by the lower control arm and measure the joints vertical movement.


Raise the vehicle by the subframe and turn the steering wheel and listen for a popping noise.
Engineering
1 answer:
Aleks04 [339]3 years ago
5 0

he following would be the correct method to check the load bearing joint is Raise the vehicle by the subframe and turn the steering wheel and listen for a popping noise.

Explanation:

  • Ball joints on a vehicle equipped with MacPherson struts are being inspected for wear. It can be checked by raising the vehicle by the subframe and turn the steering wheel and listen for a popping noise.
  • When a joint of CV becomes rusted or damaged, the flexibility of axle becomes out of order and starts making a constant clicking noise whenever the wheels are turned around.
  • The struts are the most important part of the suspension system.
  • The metallic clunking noise is found to be one of the most noticeable and frequent symptoms that shows of a bad ball joint which gives a bad clunking or knocking noise whenever the suspension operates in an up and down motion.
  • The ball joint can be broken in the following ways:
  • the ball detaching from the socket and stud breakage, nonetheless of the type of breakage, but it is catastrophic.
  • When the joint of the ball completely breaks down, the wheel becomes free to move in all the directions.

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The Double.parseDouble() method requires a String argument, but it fails if the String cannot be converted to a floating-point n
LuckyWell [14K]

Answer:

  1. import java.util.Scanner;
  2. public class TryToParseDouble {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        double num;
  6.        try{
  7.            System.out.print("Input a number: ");
  8.            num = Double.parseDouble(input.nextLine());
  9.        }catch(NumberFormatException e){
  10.            num = 0;
  11.            System.out.println("Invalid input! It should be a number in double type");
  12.        }
  13.        System.out.println(num);
  14.    }
  15. }

Explanation:

Firstly, create a Scanner object to get user input (Line 5).

Next, create a try block and prompt user to input a number and use Double.parseDouble() method to convert the input to double type in the block (Line 8-10).

Next, create a catch block to catch a NumberFormatException. In the Catch block, set the num to zero and then print out a message to inform user about the invalid input (Line 12-14).

Lastly, display the number (Line 16).

5 0
3 years ago
(a) Show how two 2-to-1 multiplexers (with no added gates) could be connected to form a 3-to-1 MUX. Input selection should be as
Llana [10]

Answer:

Explanation:

a) Show how two 2-to-1 multiplexers (with no added gates) could be connected to form a 3-to-1 MUX. Input selection should be as follows: If AB = 00, select I0 If AB = 01, select I1 If AB = 1− (B is a don’t-care), select I2

We are to show how Two-2-to -1 multiplexers could be connected to form 3-to-1 MUX

If AB = 00 select I_o

If AB = 01 select I_1

If AB = 1_(B is don't care), select I_2

However, the truth table is attached and shown in the first file below.

Also, the free- body diagram for 2- to - 1 MUX is shown in the second diagram attached below.

b) We are show how  two 4-to-1 and one 2-to-1 multiplexers could be connected to form an 8-to-1 MUX with three control inputs.

The perfect illustration showing how they are connected in displayed in the third free-body diagram attached below.

Where ; I_o , I_1, I_2, I_3, I_4, I_5, I_6, I_7 are the inputs of the multiplexer and Z is the output.

c)  Show how four 2-to-1 and one 4-to-1 multiplexers could be connected to form an 8-to-1 MUX with three control inputs.

For  four 2-to-1 and one 4-to-1 multiplexers could be connected to form an 8-to-1 MUX with three control inputs, we have a perfect illustration of the diagram in the last( which is the fourth) diagram attached below.

Where ; I_o , I_1, I_2, I_3, I_4, I_5, I_6, I_7 are the inputs of the multiplexer and Z is the output

5 0
4 years ago
Câu 1: Tìm từ trong 2 câu thơ sau liên quan đến các từ: hình chiếu, tia chiếu, mặt phẳng chiếu.
xeze [42]

Explanation:

are bhai brainly aap english me questions kar ne ko hai

ye kon si bhasha hai ??????

4 0
3 years ago
6.
Licemer1 [7]

Answer:

d

none of the above

hope this is helpful

7 0
3 years ago
What type of bridge is the sunshine skyway bridge?
sdas [7]

Answer:

That's either a cable-stayed bridge or a cantilever bridge

6 0
3 years ago
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