Just some random stufff

On a given day, a barometer at the base of the Washington Monument reads 29.97 in. of mercury. What would the barometer reading

Umnica [9.8K]

Answer:

The barometer reading will be 29.43 in

Explanation:

Using the formula of pressure variation

p2 - p1 = -yair * H

= 7.65 * $10^{-2} \frac{lb}{ft^{3} } * 500 ft\\$

= 38.5 $\frac{lb}{ft^{2} }$

According to the relationship between the pressure and the height of the mercury column

p = yHg * h --> where yHg and h is the barometer reading

yHg $(\frac{29.97}{12} ft)$ - yHg * h1 = 38.5 $\frac{lb}{ft^{2} }$

h1 = ( $\frac{29.97}{12} ft$ ) - $\frac{38.5 \frac{lb}{ft^{2} } }{847 \frac{lb}{ft^{3} } }$

$[(\frac{29.97}{12} ft) - 0.0455 ft] - 12 \frac{in}{ft} \\\\h1 = 29.43 in$

8 0

4 years ago

8. Two 40 ft long wires made of differing materials are supported from the ceiling of a testing laboratory. Wire (1) is made of

san4es73 [151]

Answer:

Material K has a modulus of elasticity E=3.389× 10¹¹ Pa

Material H has a modulus of elasticity E=1.009 × 10⁹ Pa

Material K has higher value of modulus of elasticity than material H

Material K is stiffer.

Explanation:

Wire 1 material H

Length=L = 40 ft =12.192 m

Diameter= 3/8 in = 0.009525 m

Area= A= πr²,where r=0.009525/2 =0.004763

A=3.142*0.004763² =0.00007126 m²

Force, F= 225 lb= 225*4.45 =1001.25 N

Change in length =Δ L= 0.10 in = 0.00254

To find modulus of elasticity apply'

E=F*L/A*ΔL

E=1001.25*12.192/(0.004763*0.00254)

E= 1009027923.58 Pa

E=1.009 × 10⁹ Pa

For Wire 2 material K

Length=L= 40 ft =12.192 m

Diameter = 3/16 in = 0.1875 in = 0.004763 m

Area= πr² = 3.142 * (0.004763/2)² = 0.00000567154 m²

Force, F= 225 lb= 225*4.45 =1001.25 N

Change in length =Δ L= 0.25 in =0.00635 m

To find modulus of elasticity apply'

E=F*L/A*ΔL

E= (1001.25*12.192)/(0.00000567154 * 0.00635 )

E=338955422575 Pa

E=3.389× 10¹¹ Pa

Material K has a greater modulus of elasticity

The material with higher value of E is stiffer than that with low value of E.The stiffer material is K.

8 0

3 years ago

After having done the hand calculation and pseudocode for a program that models inflating a spherical balloon, now implement the

vampirchik [111]

Answer:

Explanation:

CODE :

import java.util.Scanner; // required imports for the class

class Balloon { // class to run the code

public static void main(String[] args) { // driver method

Scanner in = new Scanner(System.in); // scanner class to get the data

System.out.print("Diameter: "); // message

double diameter = in.nextDouble(); // prompt

double growth = 1; // local variables

int c = 0;

while (c < 10) { // iterate over the loop

double radius = diameter / 2; // calculate the radius

double vol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the initial volume

diameter = growth + diameter; // update the diamter

System.out.printf("\nIncrease in the Diameter is : %.0f", growth); // message

System.out.println("\nNew Diameter is : " + diameter); // print the diameter

radius = diameter / 2; // calculate the new diameter

double growthvol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the new volume

System.out.printf("Increase in the Volume is : %.0f", growthvol - vol); // message

System.out.println("\nNew Volume is : " + growthvol); // message

c++; // increment the count

}

OUTPUT :

run 1 :

Diameter: 10