Answer:
It can be concluded that the star is moving away from the observer.
Explanation:
Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).
The wavelength at rest for this case is 434 nm and 410 nm (
, 
)
Since, 
(444nm) is greater than 
(434 nm) and (420nm) is greater than (410 nm), it can be concluded that the star is moving away from the observer
When the two-vehicle collides transformation of the energy is done in terms of kinetic energy.
<h3>What is the law of conservation of energy?</h3>
According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.
The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.
In the above problem, the Vehicle get collides so that the kinetic energy of the vehicle is converted into the kinetic energy of another vehicle the speed of the vehicle will reduce when they collide.
Momentum also gets conserved when the two vehicles collide.
Hence, the transformation of the energy is done in terms of kinetic energy.
To learn more about the law of conservation of energy, refer to brainly.com/question/2137260.
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<h2>K.E/P.E = m/k tan²φ x ω²</h2>
Explanation:
The given position of block x = x₀ cos(ωt + φ)
The velocity of block v = dx/dt = - x₀ sin(ωt + φ) x ω
The kinetic energy = 1/2 mv² = 1/2 m x₀² sin²(ωt + φ) x ω²
The potential energy of spring = 1/2 k x² , where k is the spring constant
Thus P.E = 1/2 x k x x₀² cos²(ωt + φ)
When t = 0
K.E = 1/2 m x₀²sin²φ x ω²
P.E = 1/2 k x₀² cos²φ
Dividing these , we have
K.E/P.E = m/k tan²φ x ω²
The answer to your question is B. <span>Analgesics. Hope that helps.</span>
Answer:
There is pressure on both the in and outsides of the balloon: high inside and low outside, respectively. In terms of air mass, high pressure has greater activity and tends to move upward (balloon rises); whereas low presssure, being slower, descends (balloon descends).
Explanation:
