Explanation:
Amount of heat supplied (Q) = 24500 J
Mass (m) = 2 kg
Initial temperature (t1) = 20 ° C
Final temperature (t2) = 35 ° C
Difference in temperature (dt) = t2 - t1 = ( 35 - 20) °C = 15 ° C
Now Specific heat capacity (S) = ?
We know we have the formula;
Q = m * s * dt
24500 = 2 * s * 15
24500 = 30 S
S = 24500 / 30
S = 816.67 J / Kg ° C
The specific heat capacity is 816.67 J/kg°C.
Hope it will help :)
Answer:
volume of air breath = 495.75 mL per min
Explanation:
given data
oxygen required = 2.4 × 10² mL / Min = 240 mL
inhaled air = 20 %
exhaled air = 16 %
to find out
volume of air per breath
solution
we know here that breathes 12 time every minute
and we consider here air breath = y per min
we know oxygen remain in body = 20 % - 16 % = 4%
and required 12 time air breath
so air required = 240 / 12 = 19.83 mL
so oxygen breath equation will be
y × 4% = 19.83
y = 19.83 / 0.04
y = 495.75
so volume of air breath = 495.75 mL per min
Answer:
v = 1.36 cm / y
Explanation:
For this exercise we must assume that the displacement of the plates is constant over time, so we will use the kinematic relationships for the uniform movement
v = d / t
We reduce the quantities to the SI system
d = 320 km (1000 m / 1km) (100 cm / 1 m)
d = 3.2 107 cm
let's calculate
v = 32.107 / 23.5 106
v = 1.36 cm / y
The answer to this question is 2400Hz
The initial volume of the gas is
while its final volume is
so its variation of volume is
The pressure is constant, and it is
Therefore the work done by the gas is
where the negative sign means the work is done by the surrounding on the gas.
The heat energy given to the gas is
And the change in internal energy of the gas can be found by using the first law of thermodynamics:
where the positive sign means the internal energy of the gas has increased.