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alexira [117]
3 years ago
9

What makes the world go round?

Physics
1 answer:
sineoko [7]3 years ago
6 0
The suns gravitational pull
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A converging lens is also known as a<br><br> •convex<br> •concave<br> •double<br> •refracted
Leni [432]

Answer:

Convex lens

Explanation:

hope this helps

4 0
3 years ago
Read 2 more answers
The correct equation for the x component of a vector named A with an angle measured from the x axis would be which of the follow
Lady_Fox [76]

Answer:

Acosθ

Explanation:

The x-component of a vector is defined as :

Magnitude * cosine of the angle

Maginitude * cosθ

The magnitude is represented as A

Hence, horizontal, x - component of the vector is :

Acosθ

Furthermore,

The y-component is taken as the sin of the of the angle multiplied by the magnitude

Vertical, y component : Asinθ

8 0
3 years ago
What is the magnitude of the electric force of attraction between an iron nucleus (q=+26e) and its innermost electron if the dis
iris [78.8K]

Answer:

The magnitude of the force on an electron is 0.069 N.

Explanation:

Given that,

Distance between 1.70 A from the plutonium nucleus, d=1.5\times 10^{-12}\ m

The number of electron in iron nucleus is +26e.

To find,

The magnitude of the force between an iron nucleus.

Solution,

Total charge in the plutonium nucleus is, q=26\times 1.6\times 10^{-19}=4.16\times 10^{-18}\ C. The electric force between charges is given by :

F=\dfrac{kq^2}{d^2}

F=\dfrac{9\times 10^9\times (4.16\times 10^{-18})^2}{(1.5\times 10^{-12})^2}

F = 0.069 N

So, the magnitude of the force on an electron is 0.069 N. Hence, this is the required solution.

4 0
3 years ago
Which group occupies the large middle section of the periodic table?
olga2289 [7]
This section, known as the D-block, consists of Transition metals.
3 0
4 years ago
If an object has no acceleration, can you conclude that no forces are exerted on it
MrMuchimi

No. It has no acceleration, which just means that the forces acting on it are equal and opposite, not that there are no forces exerted on it.

But if you're talking about the resulting Net Force, then yes you can conclude there is no Net Force acting on an object with no acceleration.

3 0
3 years ago
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