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alexira [117]
3 years ago
9

What makes the world go round?

Physics
1 answer:
sineoko [7]3 years ago
6 0
The suns gravitational pull
You might be interested in
Roughly to what height would a 5 kg stone need to be raised in order to have the same stored energy as the energy stored in the
hoa [83]

8.16m is the required height, a 5kg stone need to be raised.

One sort of potential energy is gravitational potential energy, which is equal to the product of the object's mass (m), the gravitational acceleration (g), and the object's height (h) as measured in relation to the ground's surface (the body).

We obtain the formula by considering the work done in raising a mass m through a height h.

Work in elevating mass m through height h is equal to force times distance.

The force must be greater than the mass m's weight, hence F = mg.

Work done = mgh = gravitational potential energy

Energy =  Mass of the object × gravitational acceleration × height.

Mass of the stone = 5kg

Equating ;

∴ 400 J = 5 kg × 9.8 m/s² × height

  Height = 8.16 m

Therefore, 8.16m is the required height.

Learn more about energy here:

brainly.com/question/1242059

#SPJ1

8 0
2 years ago
Does the air exert a buoyant force on all objects in air or only on objects such as balloons that are very light for their size?
Citrus2011 [14]

Answer:

See explanation

Explanation:

Solution:-

Buoyancy is the force that causes objects to float. It is the force exerted on an object that is partly or wholly immersed in a fluid. Buoyancy is caused by the differences in pressure acting on opposite sides of an object immersed in a static fluid. It is also known as the buoyant force. Buoyancy is the phenomena due to Buoyant Force.

It is as an upward force exerted by a fluid that opposes the weight of an object immersed in a fluid. As we know, the pressure in a fluid column increases with depth. Thus, the pressure at the bottom of an object submerged in the fluid is greater than that at the top. The difference in this pressure results in a net upward force on the object which we define as buoyancy.

- The formula for buoyant force (Fb) is given:

                           Fb = ρ*g*V

- The force acts on all objects. However, it depends on the fluid density and amount of volume displaced.

- The Buoyant force exerted by air with density = 1.225 kg/m^3 on an object with volume (V) is:

                          Fb = ρ*g*V = 1.225*9.81*V = 12.02*V

- For the similar object with mass (m), the downward weight would be:

                           W = m*g

- For the object to float the buoyant force (Fb) must be greater than weight of the object:

                          Fb > W

                          12.02*V > m*9.81

                          V / m > 0.816

- The ratio of V / m must be at-least = 0.816.

- Assuming the object is fully immersed in air, then the volume displaced V = ρ_material*V

                         ρ_material < 1 / 0.816

                        ρ_material < 1.225 or ( ρ_air )

- So the for an object to float in air its material density must always be less than that of air. That why in balloons lighter gas is used which have density less than that of air like Helium.          

4 0
3 years ago
Which of the following changes will increase the frequency of an oscillating pendulum?
igor_vitrenko [27]

Answer:

b because we apply Hooke's law

Explanation:

Hooke's law

7 0
3 years ago
At a drag race, the light turns green and 0.00125 hours later, a dragster is traveling 300 miles per hour. Calculate the acceler
Talja [164]

Answer:

240000 mph² or miles/hour²

Explanation:

<em>Use the formula</em>

<h3>acceleration = change in velocity ÷ time</h3>

change in velocity = 300 mph - 0 mph (final velocity - intial velocity)

time = 0.00125 hours

<em>Substitute the values into the formula:</em>

acceleration = 300 ÷ 0.00125 = 240000 mph²

4 0
3 years ago
67. Race Car A race car is slowed with a constant accel-
Alla [95]

Answer:

<em>a. 137.5 m</em>

<em>b. 550 m</em>

Explanation:

<u>Accelerated Motion </u>

If an object is changing its velocity at a constant rate, it has a uniformly accelerated motion. When the object is moving in one fixed axis, then the sign of the acceleration is negative if the object is braking, and positive if the object is increasing its speed.

The initial speed vo, final speed vt, acceleration a, and distance traveled x are related by the formula

v_f^2=v_o^2+2ax

a. The Race Car A has an initial speed of 55 m/s and it's said to stop. We must find at what distance it goes to vf=0. This means that the above formula becomes

0=v_o^2+2ax

Solving for x

\displaystyle x=-\frac{v_o^2}{2a}

The acceleration is -11\ m/s^2, negative because it's against the movement. Thus

\displaystyle x=-\frac{55^2}{2\times (-11)}

x=137.5\ m

b. If the car is going twice as fast (v0=110 m/s), then  

\displaystyle x=-\frac{110^2}{2\times (-11)}

x=550\ m

6 0
3 years ago
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