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8_murik_8 [283]
3 years ago
11

What is the mass percent of calcium chloride if 57 g of CaCl2 is dissolved in 334 g of water?

Chemistry
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

Solubility in water Anhydrous: 74.5 g/100 mL (20 °C) Hexahydrate: 49.4 g/100 mL (−25 °C) 59.5 g/100 mL (0 °C) 65 g/100 mL (10 °C) 81.1 g/100 mL (25 °C) 102.2 g/100 mL (30.2 °C) α-Tetrahydrate: 90.8 g/100 mL (20 °C) 114.4 g/100 mL (40 °C) Dihydrate: 134.5 g/100 mL (60 °C) 152.4 g/100 mL (100 °C)

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Alice added sodium chloride to water and stirred the water for several minutes. Alice is most likely trying to demonstrate that
SashulF [63]

Answer is: 2. can dissolve.

Ionic compounds separates into particles (ions) in water because of their ionic bond.

For example sodium chloride is ionic compound and strong electrolyte and dissociates in water on hydrated sodium cations and chlorine anions:

NaCl(aq) → Na⁺(aq) + Cl⁻(aq).

Ionic bond is the electrostatic attraction between oppositely charged ions (cations and anions).

6 0
3 years ago
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The products in a decomposition reaction _____. are compounds can be elements or compounds are elements include an element and a
ivann1987 [24]

Answer:

compounds are elements include an element and a compound

Explanation:

elements in the decomposition reaction is the substance that cannot be separated into simpler substances. Compounds, technically act as a reactant in the decomposition reaction, but since the reaction breakdown one substance into two or more, sometimes it exists in the product

7 0
3 years ago
How many miles of H2O are produced when 0.322 mol of octane is burned?
victus00 [196]

Answer:

alot of h2o

Explanation:

8 0
3 years ago
Molecular formula for C4H10
Gnesinka [82]
I think this is what you mean:

    H H H H
H-C-C-C-C-H
    H H H H

OR 

<span>CH3CH2CH2CH3
</span>
If not, clarify and I will be happy to help.
6 0
3 years ago
HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED
kramer

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

5 0
3 years ago
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