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Aleksandr [31]
3 years ago
5

Is 2Zn + 2HCI = ZnCL2 + H2 balanced or unbalanced

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
7 0
Unbalanced it should be 2Zn+2Hcl=2ZnCl2+H2
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What is the main difference between extensive and intensive physical properties?
mr_godi [17]
Extensive properties, such as mass and volume, depend on the amount of matter being measured. Intensive properties, such as density and color, do not depend on the amount of the substance present.
8 0
3 years ago
Read 2 more answers
Determine the number of atoms of O in 92.3 moles of Cr3(PO4)2
Irina18 [472]

739 is the number of atoms of O in 92.3 moles of Cr3(PO4)2.

Explanation:

Molecular formula given is  = Cr3(PO4)2

number of moles of the compound is 92.3 moles

number of 0 atoms in 92.3 moles =?

From the chemical formula 1 mole of the compound has 8 atoms of oxygen

So, it can be written as

1 mole Cr3(PO4)2 has 8 atoms of oxygen

92.3 moles of Cr3(PO4)2 has x atoms of oxygen

\frac{8}{1} = \frac{x}{92.3}

x = 8 x 92.3

x = 738.4 atoms

There will be 739 oxygen atoms in the 92.3 moles of Cr3(PO4)2.

4 0
3 years ago
A student sets up the following equation to convert a measurement. The (?) Stands for a number the student is going to calculate
Vika [28.1K]

Answer:

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 3.0 \times 10^{-7} \text{ m}^{3}  

Explanation:

0.030 cm³ × ? = x m³

You want to convert cubic centimetres to cubic metres, so you multiply the cubic centimetres by a conversion factor.

For example, you know that centi means "× 10⁻²", so  

1 cm = 10⁻² m

If we divide each side by 1 cm, we get 1 = (10⁻² m/1 cm).

If we divide each side by 10⁻² m, we get (1 cm/10⁻² m) = 1.

So, we can use either (10⁻² m/1 cm) or (1 cm/10⁻² m) as a conversion factor, because each fraction equals one.

We choose the former because it has the desired units on top.

The "cm" is cubed, so we must cube the conversion factor.

The calculation becomes

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 0.30 \times 10^{-6}\text{ m}^{3} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}\\\\\textbf{0.30 cm}^{\mathbf{3}} \times \left (\dfrac{\mathbf{10^{-2}}\textbf{ m}}{\textbf{1 cm}}\right )^{\mathbf{3}} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}

7 0
3 years ago
How much water would I need to add to 700 mL of a 2.7 M KCl solution to make a 1.0 M solution?
geniusboy [140]

Answer:

1190\ \text{mL}

Explanation:

M_1 = Initial Concentration of KCl = 2.7 M

V_1 = Volume of KCl = 1 M

M_2 = Final concentration of KCl = 1 M

V_2 = Amount of water

We have the relation

M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}

The amount of water that is to be added is 1890-700=1190\ \text{mL}.

3 0
2 years ago
CI2+NaOH⇒NaCI+NaOCI+H20<br> is there a way to balance this?
Snowcat [4.5K]
I really don’t think so…
4 0
3 years ago
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