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Dmitrij [34]
3 years ago
11

When a warm front passes your location, the temperature rises rapidly. As a result, air density:

Chemistry
2 answers:
sukhopar [10]3 years ago
8 0
The air density decreases.
deff fn [24]3 years ago
3 0

Answer:

decreases

Explanation:

As you know when the temperature of a medium decreases, the density increases, the majority of the solids present in nature depende of a certain temperature, when they heat up they tend to go to a liquid form and then to gas, so if the temperature in the are rises rapidly the densitiy of the air would decrease as it is expanding because of the rise of the temperature.

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What is the most likely result of the pollution of a fresh water resource?
Troyanec [42]

Answer:

Loss of biodiversity in the wetlands.

Explanation: Pollution can be defined as the emission of toxic, poisonous and harmful chemical substances which are capable of causing environmental degradation and contamination.

Nitrogen pollution enters Earth’s freshwater resources from a variety of human activities, including the use of fertilizers and pesticides in agriculture. This nitrogen pollution has a negative effect on plants and animals living in fresh water. Certain wetland plants, however, are able to purify the water and restore it to its non-polluted state.

Hence, what would most likely increase the negative effects of nitrogen pollution is a loss of biodiversity in the wetlands i.e the various species of animal and plants.

6 0
3 years ago
Hi what is kinematic??
Fiesta28 [93]

Answer:

Kinematics is a branch of physics concerned with the geometrically possible motion of a body or system of bodies without considering the  forces which are involved

Hope it helpsssss.!!!!

7 0
3 years ago
If 1.9 kJ of heat is transferred to 96 g aluminum at 113°C, what would the
erastova [34]

Answer:

T2 = 135.1°C

Explanation:

Given data:

Mass of water = 96 g

Initial temperature = 113°C

Final temperature = ?

Amount of energy transfer = 1.9 Kj (1.9×1000 = 1900 j)

Specific heat capacity of aluminium = 0.897 j/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Now we will put the values in formula.

Q = m.c. ΔT

1900 j = 96 g × 0.897 j/g.°C × T2 - 113°C

1900 j = 86.112 j/°C × T2 - 113°C

1900 j / 86.112 j/°C = T2 - 113°C

22.1°C + 113°C =  T2

T2 = 135.1°C

4 0
3 years ago
Will mark brilliant pls help question is above​
Degger [83]

Answer:

a.) The garden plants provide energy to all the other organisms. While not every organism consumes garden plants directly, every organism's food lineage can be traced to garden plants. For instance, while ground beetles do not directly consume garden plants, they do eat snails, and snails eat garden plants.

b.) The slug population might increase is the aphid population decreased because there would be less competition for food resources. Both populations consume garden plants, and there is only a finite number of garden plants. Therefore, there is a limit that each population can consume. If there were less aphids eating the garden plants, there would be more left for the slugs. Less starving slugs would lead to greater reproduction and thus a higher slug population.

4 0
2 years ago
0.22 L of HNO3 is titrated to equivalence using 0.10 L of 0.1 MNaOH. What is the concentration of the HNO3?
White raven [17]

Answer:- Molarity of the acid solution is 0.045M.

Solution:- The balanced equation for the reaction of given acid and base is:

HNO_3+NaOH\rightarrow NaNO_3+H_2O

From the balanced equation, they react in 1:1 mol ratio. So, we could easily solve the problem using the equation:

M_aV_a=M_bV_b

where, M_a is the molarity of acid, M_b is the molarity of base, V_a is the volume of acid and V_b is the volume of base.

Let's plug in the given values in the equation:

M_a(0.22L)=0.1M(0.10L)

on rearranging the above equation:

M_a=\frac{0.1M(0.10L)}{0.22L}

M_a = 0.045M

So, the molarity of the acid solution is 0.045M.

3 0
3 years ago
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