When a warm front passes your location, the temperature rises rapidly. As a result, air density:
2 answers:
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The answer is the specific heat of the gold is 0.129 J/gC .
<h3>What is Calorimetry ?</h3>It is an experimental method that allows one to calculate the heat change in a chemical process.
Calorimeter is just a reaction vessel. It could be a foam cup, a soda can, or a commercially available bomb calorimeter
Where q represents the heat change in the reaction, the calorimeter and the water. Since you are only measuring temperature, you will need to calculate the heat using it.
The change in heat of the gold is given by:
The change in heat of the water is given by:
m is the mass of water in the calorimeter in grams,
and delta T is the change in temperature.
where is the specific heat of water, which is 4.184 J/gC
mass of water = 25 g of water.
Temperature T₁ = 25°C
Final Temperature = 38.18 °C
Difference between temperature = 13.18 °C
For a Foam Cup Calorimeter
Therefore the the specific heat of the gold is 0.129 J/gC
To know more about Calorimeter
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The resistance of the appliance is 64.1 Ω.
<u>Explanation:</u>
As per the Ohm's law, which states that the electric current is in direct proportion to the voltage and is in inverse proportion to the resistance. It is given by the expression as,
V = IR
Where V is the voltage (V) = 150.0 V
I is the current (amps) = 2.34 amps
R is the resistance (ohm) or Ω = ?
Now we have to rearrange the equation to get the resistance as,
Now we have to plug in the values as,
= 64.1 Ω
So the resistance of the appliance is 64.1 Ω.