Answer: a. the inhibitor will decrease the rate of reaction.
Explanation: The rate of the reaction is affected by addition of inhibitors which are also called as negative catalysts as they decrease the rate of reaction unlike catalysts which enhance the rate of reaction.
Inhibitors delay, slow or prevent the chemical reactions by binding with the substrate or the catalyst and hence prevent them to function normally.
Answer:
107.87 grams
Explanation:
One mole of silver weighs 107.87 grams
.
Answer:
25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.
Explanation:
The balanced reaction is:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
- C₂H₂: 2 moles
- O₂: 5 moles
- CO₂: 4 moles
- H₂O: 2 moles
The molar mass of each compound is:
- C₂H₂: 26 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- C₂H₂: 2 moles* 26 g/mole= 52 g
- O₂: 5 moles* 32 g/mole= 160 g
- CO₂: 4 moles* 44 g/mole= 176 g
- H₂O: 2 moles* 18 g/mole= 36 g
Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

mass of O₂= 25.08 grams
<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>
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