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Ede4ka [16]
3 years ago
10

What is the mass of 2.50L of SO2 gas at stp

Chemistry
2 answers:
maxonik [38]3 years ago
5 0
STP is abbreviation for Standard Temperature and Pressure at which the temperature is 273 K and pressure is 1 atm 
- At these conditions the molar volume is equal to 22.4 L
so 1 mole of SO₂ volume = 22.4 L 
     ? mole of SO₂ volume = 2.5 L
number of moles = 2.5 / 22.4 = 0.1116 mol
mass of SO₂ = 0.1116 * 64.063 = 7.15 g
stira [4]3 years ago
4 0

Answer: 4.84 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass, occupies 22.4 L of volume at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given volume}}{\text{Molar volume}}=\frac{2.50}{22.4}=0.11

1 mole of SO_2 weighs = 44 g

0.11 moles of SO_2 weigh = \frac{44}1}\times 0.11=4.84g

Thus mass of 2.5 L of SO_2 weigh 4.84 grams.

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The economic regulation are the provisions through which the government intervenes in the markets to set prices or quantities of production, or establish technical specifications and in general, restrictions that must be met by citizens and companies to participate in a market.

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16 H + + 2Cr2O72- + C2H5OH → 4 Cr3 + +11H2O +2CO2

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3. A compound consists of 91.63 grams of carbon, 7.69 grams of hydrogen and 40.81 grams of
Vikentia [17]

Answer:

Molecular formula = C₁₂H₁₂O₄

Empirical formula is C₃H₃O.

Explanation:

Given data:

Mass of C = 91.63 g

Mass of H = 7.69 g

Mass pf O = 40.81 g

Molar mass of compound = 220 g/mol

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of H = 7.69 / 1.01 = 7.61

Number of gram atoms of O = 40.81 / 16 = 2.55

Number of gram atoms of C = 91.63 / 12 = 7.64

Atomic ratio:

            C                      :      H                :         O

           7.64/2.55          :    7.61 /2.55    :       2.55/2.55

               3                     :          3               :        1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 3×12+ 3×1.01 +16 = 55.03

n = 220 / 55.03

n = 4

Molecular formula = 4 (empirical formula)

Molecular formula = 4 (C₃H₃O)

Molecular formula = C₁₂H₁₂O₄

8 0
3 years ago
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