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Ede4ka [16]
3 years ago
10

What is the mass of 2.50L of SO2 gas at stp

Chemistry
2 answers:
maxonik [38]3 years ago
5 0
STP is abbreviation for Standard Temperature and Pressure at which the temperature is 273 K and pressure is 1 atm 
- At these conditions the molar volume is equal to 22.4 L
so 1 mole of SO₂ volume = 22.4 L 
     ? mole of SO₂ volume = 2.5 L
number of moles = 2.5 / 22.4 = 0.1116 mol
mass of SO₂ = 0.1116 * 64.063 = 7.15 g
stira [4]3 years ago
4 0

Answer: 4.84 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass, occupies 22.4 L of volume at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given volume}}{\text{Molar volume}}=\frac{2.50}{22.4}=0.11

1 mole of SO_2 weighs = 44 g

0.11 moles of SO_2 weigh = \frac{44}1}\times 0.11=4.84g

Thus mass of 2.5 L of SO_2 weigh 4.84 grams.

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Adding an inhibitor to a chemical reaction will have which of the following effects on a reaction?
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Answer: a. the inhibitor will decrease the rate of reaction.

Explanation: The rate of the reaction is affected by addition of inhibitors which are also called as negative catalysts as they decrease the rate of reaction unlike catalysts which enhance the rate of reaction.

Inhibitors delay, slow or prevent the chemical reactions by binding with the substrate or the catalyst and hence prevent them to function normally.


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3 years ago
Grams. Number only, rounded to the<br> One mole of silver weighs<br> hundredths place (.01) *Y
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Explanation:

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3 years ago
How many grams of O2 are needed to react with 8.15 g of C2H2?
xxTIMURxx [149]

Answer:

25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

  • C₂H₂: 2 moles
  • O₂: 5 moles
  • CO₂: 4 moles
  • H₂O: 2 moles

The molar mass of each compound is:

  • C₂H₂: 26 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₂H₂: 2 moles* 26 g/mole= 52 g
  • O₂: 5 moles* 32 g/mole= 160 g
  • CO₂: 4 moles* 44 g/mole= 176 g
  • H₂O: 2 moles* 18 g/mole= 36 g

Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

mass of O_{2} =\frac{8.15 grams of C_{2} H_{2}*160 grams of O_{2}  }{52 grams of C_{2} H_{2}}

mass of O₂= 25.08 grams

<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>

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