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Readme [11.4K]
3 years ago
9

What are limitations of the calculated and indirect volume measurement?

Physics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

Answer: Not suitable for large volume and irregular shaped object.

Explanation: The answer refers to a high school physics experiment where candidates are required to determine the density of an object which is regularly or irregularly shaped.  

Therefore, an object whose shape is irregular although its volume might be as same as a regular shape i.e, (cuboid), might be difficult to fit in the container provided for the density.

tresset_1 [31]3 years ago
3 0

Answer: The calculated volume measures the side of the cube to get the volume. An indirect measurement of volume measures the displacement of a liquid by a solid.

Explanation:

Volume is the amount of  the space occupied by an object. Volume can be used to measure the amount of the space occupied by the solid, liquid and gas.

When the direct measurement is not possible then the indirect measurement is used by taking the small part that object to calculate the whole part of that.  

The limitations of the calculated and indirect volume measurement are as follows,

The calculated volume measures the side of the cube to get the volume. An indirect measurement of volume measure the displacement of a liquid by a solid. For example, the volume of the liquid is displaced by the sponge is not equal to the volume of the sponge.

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Explanation:

The intensity of a sound wave is given by the relation

         I = P / A = ½ ρ v (2π f s_{max})²

         I = (½ ρ v 4π² s_{max}²) f²

a) with the initial condition let's call the intensity Io

        cte = (½ ρ v 4π² s_{max}²)

         I₀ = cte s² f₀²

        I₀ = cte 10 6

If frequency is increase f = 2.20 10³ Hz

         I = constant (2.20 10³) 2

         I = cte 4.84 10⁶

let's find the relationship of the two quantities

        I / Io = 4.84

        I = 4.84 Io

        I = 4.84 0.750

        I = 3.63 W / m²

b) in this case the frequency is reduced to f = 0.250 10³ Hz and the displacement s = 4 s or

        I = cte (f s)²

        I = constant (0.250 10³ 4)²

 

        I = cte 1 10⁶

         

the relationship

        I / Io = 1

        I = Io

        I = 0.750 W / m²

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2 years ago
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