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3 years ago

What are limitations of the calculated and indirect volume measurement?

Physics

2 answers:

PilotLPTM [1.2K]3 years ago

7 0

Answer: Not suitable for large volume and irregular shaped object.

Explanation: The answer refers to a high school physics experiment where candidates are required to determine the density of an object which is regularly or irregularly shaped.

Therefore, an object whose shape is irregular although its volume might be as same as a regular shape i.e, (cuboid), might be difficult to fit in the container provided for the density.

tresset_1 [31]3 years ago

3 0

Answer: The calculated volume measures the side of the cube to get the volume. An indirect measurement of volume measures the displacement of a liquid by a solid.

Explanation:

Volume is the amount of the space occupied by an object. Volume can be used to measure the amount of the space occupied by the solid, liquid and gas.

When the direct measurement is not possible then the indirect measurement is used by taking the small part that object to calculate the whole part of that.

The limitations of the calculated and indirect volume measurement are as follows,

The calculated volume measures the side of the cube to get the volume. An indirect measurement of volume measure the displacement of a liquid by a solid. For example, the volume of the liquid is displaced by the sponge is not equal to the volume of the sponge.

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Explanation:

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Two inductors, L1 and L2, are in parallel. L1 has a value of 25 mH and L2 a value of 50 mH. The parallel combination is in serie

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Answer:

Explanation:

For parallel inductors ,

$\frac{1}{L_R} = \frac{1}{L_1} +\frac{1}{L_2}$

$\frac{1}{L_R} =\frac{1}{25} +\frac{1}{50}$

$L_R=16.67 mH.$

For series combination

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= 16.67 + 20

= 36.67 mH .

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= ω $L_{total}$ where ω is angular frequency

= 2πf $L_{total}$

= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³

= 69.1 x 10³ ohm

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3 years ago

the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67

baherus [9]

Answer:

$\theta_c = 36.78^o$

Explanation:

The relationship between the refractive index and the critical angle is given as follows:

$\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )$

where,

η = refractive index = 1.67

θc = critical angle =?

Therefore,

$\theta_c = Sin^{-1}(\frac{1}{1.67} )$

$\theta_c = 36.78^o$

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3 years ago

A rectangular loop of area A is placed in a region where the magnetic field is perpendicular to the plane of the loop. The magni

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Answer:

Induced emf, $\epsilon=-A\dfrac{B_{max}e^{-t/\tau}}{\tau}$

Explanation:

The varying magnetic field with time t is given by according to equation as :

$B=B_{max}e^{-t/\tau}$

Where

$B_{max}\ and\ t$ are constant

Let $\epsilon$ is the emf induced in the loop as a function of time. We know that the rate of change of magnetic flux is equal to the induced emf as:

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{d(BA)}{dt}$

$\epsilon=-A\dfrac{d(B)}{dt}$

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So, the induced emf in the loop as a function of time is $A\dfrac{B_{max}e^{-t/\tau}}{\tau}$ . Hence, this is the required solution.

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3 years ago

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tatiyna

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