Answer: this answer is D. That's what I think it is
Explanation:
<span>In order to determine the wavelength, we use the wave equation:
speed = frequency * wavelength
speed of light c = 3 x 10</span>⁸<span> m/s
Frequency f = 104.1 MHz = 1.041 x 10</span>⁸ Hz<span>
c = f</span>λ
λ = c / f
λ = 3 x 10⁸ / 1.041 x 10⁸
λ = 2.88 meters
The wavelength of the waves is 2.88 meters.
Answer:
d= 0.242 mm
Explanation:
Slit width (d ) = ?
Screen distance ( D ) = 1.25 m
Wave length of light λ = 600 nm
Distance of n the dark fringe from centre
= n λ D / d
Here n = 2
so
d= 0.242 mm
Answer:
Tension= 21,900N
Components of Normal force
Fnx= 17900N
Fny= 22700N
FN= 28900N
Explanation:
Tension in the cable is calculated by:
Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium
FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)
Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)
Ftorque= 2/3FBcostheta+ 4/3FWcostheta
Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°
Ftorque= 21900N
b) components of Normal force
Efx=FNx-FTcos(90-theta)=0 static equilibrium
Fnx=21900cos(90-55)=17900N
Fy=FNy+ FTsin(90-theta)-FB-FW=0
FNy= -FTsin(90-55)+FB+FW
FNy= -21900sin(35)+(1350+2250)×9.81=22700N
The Normal force
FN=sqrt(17900^2+22700^2)
FN= 28.900N
