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lozanna [386]
3 years ago
7

The energy an object has as a result of it being in motion is called? What kind of energy?

Physics
2 answers:
mariarad [96]3 years ago
5 0
Kinetic energy is motion
trasher [3.6K]3 years ago
3 0
Kinetic energy i took the test and it was correct!
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A ballet student with her arms and a leg extended spins with an initial rotational speed of 0.90rev/s . As she draws her arms an
Rainbow [258]
Initial inertia = 3.6 kg . m^2

final inertia = 0.80 kg.m^2rotational velocity final = 4.1 rev/s
rotational velocity initial = 0.90 rev/s 
lo= lf(final inertia) *  Wf(rotational velocity final)/ Wo (rotational velocity initial)

lo =  0.8*4.1 / 0.90 = 3.6 kg m2
5 0
3 years ago
You are pushing an 80.0 N wheelbarrow as shown in (Figure 1). You lift upward on the handle of the wheelbarrow so that the only
AleksandrR [38]

Answer:

Wl = 1740 N

Explanation:

maximum lift weight unaided = force exerted (F) = 650 N

length of the wheelbarrow (L) = 1.4 m

weight of the wheelbarrow (w) = 80 N

distance of center of gravity of the wheel barrow from the wheel = 0.5 m

distance of center of gravity of the load from the wheel = 0.5 m

find the weight of the load (Wl)

from the diagram attached we can see that there is going to be a rotation about the axis A. let clockwise rotation be positive

ΣT = (F x 1.4) - ((Wl x 0.5) + (w x 0.5) = 0

(F x 1.4) = ((Wl x 0.5) + (w x 0.5)

Wl =

Wl =

Wl = 1740 N

6 0
2 years ago
If a boat and its riders have a mass of 1100 kg and the boat drifts in at 1.3 m/s how much work does Sam do to stop it
andriy [413]

Answer:

-929.5Joules

Explanation:

To get the work done by sam, we will calculate the kinetic energy of sam expressed as;

KE = 1/2mv²

m is the mass = 1100kg

v is the velocity = 1.3m/s

KE = 1/2(1100)(1.3)²

KE = 550(1.69)

KE = 929.5Joules

Since Sam is opposing the direction of movement, work done by him will be a negative work i.e -929.5Joules

5 0
3 years ago
Radiation is energy that is (5 points) not transferred at all transferred by direct contact of two objects transferred by moving
BARSIC [14]
There isn't a question here so, true
3 0
3 years ago
if a cat is running at a constant speed of 10km/h for 5 s, what is its average speed and what is its instantaneous speed at 4 s?
iris [78.8K]

Here a cat is running at constant speed which is given as 10 km/h for  5s

So here the average speed is defined as total distance moved in total time interval

so here it is given by

v_{avg} = \frac{distance}{time}

since

here speed of cat is constant so it will remain the same

And hence the average speed and instantaneous speed at any instant for this duration will remain the same

so here answer would be

<em>average speed = 10 km/h</em>

<em>instantaneous speed = 10 km/h</em>

8 0
3 years ago
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