Question

A crate with mass 32.5 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 14.0 N.

Answer 1

Answer

given,

mass of crate = 32.5 Kg

horizontal force  = 14 N

initial speed, u = 0 m/s

a) acceleration produced = ?

we know,

F = m a

$a = \dfrac{F}{m}$

$a = \dfrac{14}{32.5}$

      a = 0.431 m/s²

b) using equation of motion

    t = 10 s

 $s = ut + \dfrac{1}{2}at^2$

 $s = 0 + \dfrac{1}{2}\times 0.431\times 10^2$

        s = 21.54 m

c) again using equation of motion

     v = u + at

     v = 0 + 0.431 x 10

     v = 4.31 m/s