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Elden [556K]
3 years ago
5

A crate with mass 32.5 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 14.0 N.

Physics
1 answer:
Sati [7]3 years ago
4 0

Answer

given,

mass of crate = 32.5 Kg

horizontal force  = 14 N

initial speed, u = 0 m/s

a) acceleration produced = ?

we know,

F = m a

a = \dfrac{F}{m}

a = \dfrac{14}{32.5}

      a = 0.431 m/s²

b) using equation of motion

    t = 10 s

 s = ut + \dfrac{1}{2}at^2

 s = 0 + \dfrac{1}{2}\times 0.431\times 10^2

        s = 21.54 m

c) again using equation of motion

     v = u + at

     v = 0 + 0.431 x 10

     v = 4.31 m/s

   

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Advocard [28]

Answer:

a

The total distance traveled is D  = 26760 \ m

b

The average velocity is  v_{avg} =  6.8 \ m/s

Explanation:

From the question we are told that

     The time taken for first part t_1 =  22 \ minutes = 22*60 = 1320 \ s

      The speed for the first part is  v_1 =  7.2 \ m/s

        The time taken for second part is t_2 =  36 \ minutes =  2160 \ s

        The speed for the second  part is  v_2 =  5.1 \ m/s

         The time taken for third  part is  t_3 =  8 \ minutes = 480 \ s  

          The speed for the third  part is  v_3 =  13 m/s

Generally

        distance(D)  =  velocity * time

Therefore the total distance traveled is  

         D  =  (v_1 * t_1) + (v_2 * t_2 ) + (v_3 * t_3)

substituting values

        D  =  (7.2 * 1320) + (5.1 * 2160) + (13 * 480)

        D  = 26760 \ m

Generally the average velocity is mathematically represented as

        v_{avg} =  \frac{D}{t_{total}}

Where t_{total} is the total time taken which is mathematically represented as

       t_{total}  =  1320 + 2160 + 480

      t_{total}  =3960\ s

The average velocity is

        v_{avg} =  \frac{26760}{3960}

        v_{avg} =  6.8 \ m/s

   

8 0
3 years ago
Reeti has a mass of 51.0 kg. The Gravitron, a ride that spins so fast that the floor can be removed without the riders falling,
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Answer:

L = 2774.4 kgm^{2}/s

Explanation:

Using the formula

L = mvr

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v is velocity

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L = 51×17×3.2

L = 2774.4 kgm^{2}/s

7 0
3 years ago
By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows. The pulley can be tre
tankabanditka [31]

Answer:

Mass of the pull is 77 kg

Explanation:

Here we have for

Since  the rope moves along with pulley, we have

For the first block we have

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T₁ =  3/4(m₁g) = 323.4 N

Similarly, as the acceleration of the second block is the same as the first block but in opposite direction, we have

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T₂ =  5/4(m₂g) = 134.75 N

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M = -\frac{2}{2.45} (134.75-323.4) = 77 \, kg

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kipiarov [429]

Answer:

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Which statement does NOT explain the concept of the Doppler Effect? A. As an observer moves away from a stationary sound, the so
Nookie1986 [14]

Answer:

  D

Explanation:

When the sound is moving away from the stationary object the pitch decreases according to the Doppler Effect.

4 0
3 years ago
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