All categories

3 years ago

How can one find the mechanical advantage of a pulley?

Physics

2 answers:

Alborosie3 years ago

3 0

Answer:

To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort)

Example:

For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2. The more compound the pulley is the easier the load is to lift. If you were lifting a 600kg object with 2 pulleys you would have to use enough effort to pull 300kg to lift the 600kg object! Therefore your mechanical advantage would be 2 (600/300).

MA= load/effort OR number of rope sections

ArbitrLikvidat [17]3 years ago

3 0

Count the numbers and then support whatever you are lifting (object)

You might be interested in

In which of these situations is convection most likely the main form of heat transfer? A.Warm air from a heater on the first flo

Kitty [74]

The answer is D.An ice cube melts when a person holds it in his hand
The heat from your body is causing the ice cube to melt

3 0

3 years ago

Read 2 more answers

Which of the following represents an element?

Digiron [165]

H2 is the correct answer

7 0

3 years ago

Determine the direction in which an electrical signal is carried in a typical multipolar neuron

choli [55]

The direction in which an electrical signal is carried in a typical multi-polar neuron is:
Dendrites, cell body, axon
Specialized projection of neurons are dendrites and axon. The central part of neuron is cell body. So, the electrical signal is carried in a direction that first dendrites carried the signal then it goes towards cell body and then to axon.

6 0

3 years ago

A=vf-vi/t is the equation for calculating the acceleration of an object. write out the relationship shown in the equation using

Lelechka [254]

Basically it is the difference in velocity divided by the time it takes to make that change.

3 0

3 years ago

You are on vacation in San Francisco and decide to take a cable car to see the city. A 5800-kgkg cable car goes 260 mm up a hill

Stella [2.4K]

Answer:

$4.325\times10^6J$

Explanation:

Mass of the cable car, m = 5800 kg

It goes 260 m up a hill, along a slope of $\theta=17^o$

Therefore vertical elevation of the car = $260sin\theta=260sin17^o=76.0166m$

Now, when you get into the cable car, it's velocity is zero, that is, initial kinetic energy is zero (since K.E. = $\frac{1}{2} mv^2$ ). Similarly as the car reaches the top, it halts and hence final kinetic energy is zero.

Therefore the only possible change in the cable car system is the change in it's gravitational potential energy.

Hence, total change in energy = mgh = $5800\times9.81\times76.0166J=4.325\times10^6J$

where, g = acceleration due to gravity

h = height/vertical elevation

4 0

3 years ago