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Vikentia [17]
2 years ago
6

How can one find the mechanical advantage of a pulley?

Physics
2 answers:
Alborosie2 years ago
3 0

Answer:

To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort)

Example:

For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2. The more compound the pulley is the easier the load is to lift. If you were lifting a 600kg object with 2 pulleys you would have to use enough effort to pull 300kg to lift the 600kg object! Therefore your mechanical advantage would be 2 (600/300).

               MA= load/effort OR number of rope sections

ArbitrLikvidat [17]2 years ago
3 0
Count the numbers and then support whatever you are lifting (object)
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Car a runs a red light and broadsides car b, which is stopped and waiting to make a left turn. car a has a mass of 1,800kg. car
frez [133]

The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:

mA vA + mB vB = m v

where, m is the mass in kg, v is the velocity in m/s

since m is the total mass, m = mA + mB, we can write the equation as:

mA vA + mB vB = (mA + mB) v

furthermore, car B was at a stop signal therefore vB = 0, hence

mA vA + 0 = (mA + mB) v

1800 (vA) = (1800 + 1500) (7.1 m/s)

<span>vA = 13.02 m/s</span>

7 0
3 years ago
How long does it take a vehicle to reach a velocity of 32 m/s if it accelerates from rest at a rate of 4.2 m/s^2?
Marta_Voda [28]

Answer:

7.62

Explanation:

because you have to divide 32/4.2

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4 0
3 years ago
A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for s
asambeis [7]

Answer:

I=0.0987kg.m^2

Explanation:

From the question we are told that:

Mass M=1.80kg

Deviation d=0.250

Time t=0.940s

Generally the equation for moment of inertia is mathematically given by

 I=\frac{T}{2\pi}^2(mgd)

 I=\frac{0.94}{2.3.142}^2(1.80*9.8*0.250)

 I=0.0987kgm^2

5 0
3 years ago
Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3
solong [7]

Answer:

v = 5.166 10² m / s

Explanation:

We can solve this exercise using the kinematics equations

           v = v₀ + at

as the bullet starts from rest its initial velocity is zero

           v = a t

let's calculate

           v = 6.3 10⁵   8.2 10⁻⁴

           v = 5.166 10² m / s

3 0
2 years ago
When the distance between two stars decreases by one-third, the force between them
pashok25 [27]

Answer:

the force will increase by a factor 2.25

Explanation:

The gravitational force between the two stars is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two stars

r is the distance between the stars

If the distance is decreased by one-third, it means that the new distance is 2/3 of the previous distance

r'=\frac{2}{3}r

So the new force will be

F'=G\frac{m_1 m_2}{(\frac{2}{3}r)^2}=\frac{9}{4} G\frac{m_1 m_2}{r^2}=2.25 F

So, the force will be 2.25 times the previous value.

4 0
3 years ago
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