8n downwards
since downwards force is greater than upwards just minus
Answer:
Explanation:
It is given that two identical masses is attached to the either end of the spring
with spring constant k
angular frequency of the system is given by
here
Thus
Answer: ∆y = vᵢ∆t + 0.5a(∆t)²
Explanation:
The displacement of an object travelling at a particular acceleration, with an initial velocity vi through a period of ∆t can be expressed using the displacement equation.
d = ut + 0.5at²
Where;
d = y = displacement
u = vᵢ = initial velocity
a = acceleration
t = ∆t = time taken
Therefore,
∆y = vᵢ∆t + 0.5a(∆t)²
The time required by the car to stop is 4.916 sec.
Since the car is moving with the constant deceleration we can apply the first equation of motion to calculate the time required by the car to stop.
The first equation of motion is given as
V=u+at
Here, V=final speed of the car=0 mi/h as the car stops
u =initial speed of the car=55 mi/hr=24.58 m/s
a= acceleartion =-5 m/s^2 (here negative sign indicates for deceleration)
Now applying the values in the first equation
V=u+at
0=24.58-5*t
t=4.916 sec
Therefore the car will stops in 4.916 sec.