COVALENT BOND IS THE BOND EXISTING BETWEEN 2 ATOMS THAT SHARE 6 ELECTRONS
#1
- Nephilim has very weak intermolecular forces
- So on heating it directly turns gas from solid.
#2
- Nathaline is non polar
- Water is polar
So it is not expected to dissolve in water.
#3
Empirical formula mass
n:-
- Molecular formula mass/Empirical formula mass
- 128/64
- 2
Molecular formula
- n×Empirical formula
- 2(C_5H_4)
- C_10H_8
<u>Answer:</u> The correct answer is Option C.
<u>Explanation:</u>
We are given some polyatomic ions with their oxidation states. Polyatomic ions are defined as the ions which are formed from more than 2 atoms.
We need to find out the chemical formula for ammonium phosphate.
For this, the polyatomic ions used are:
Ammonium ion - 
Phosphate ion - 
By using criss-cross method, the oxidation state of the ions are exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
Thus, the chemical formula for this compound is 
Hence, the correct answer is Option C.
Answer:
Br2+ 2H2O + SO2= 2HBr + H2SO4
Let's Compare the left side of the equation to the right side of the equation.
Left: Br= 2, H= 2, S= 1, O = 1+2
Right: Br=1, H= 1+2, S=1, O= 4
We can see that only S is balanced and not the other 3 elements.
I'll try to make each element balance.
For Br; I'll multiply by 2 on the left to make it equal to the right.
For H; Since the 2 for Br on the right affected also H, that H ( for HBr) Already has a 2, but then it adds with the other H2( for H2SO4) to give a total of 4 H on the right side. But then there's only 2 H on the left. so we multiply that 2 by a 2 ( which is written infront of the H2O to give a total of 4 H on the left side.
For O; Because of the 2 infront of the H2O, it affects the O in H2O..so now we have 2 O plus the 2 O ( in SO2) to give a total of 4 O which is equal to the right side.
Answer:
Carbons 1 and 3
Explanation:
We must remember that by definition <u>alpha carbon</u>s are the carbon (or carbons) next to the carbon that contains the main group. In this case, the main group is the carbonyl group (C = O) in the middle of the molecule. In the acetone molecule, we have three carbons, the carbons neighboring the carbon of the carbonyl group (carbon two) will be the <u>alpha carbons</u>. (Red and blue carbons or carbons one and three)
See figure 1 for further explanations.
I hope it helps!