Answer:
a.8m/s is my ans it may help you
The experiments will involve two billiard balls of known masses, m₁ and m₂, and velocities u₁ and u₂. The two are allowed to collide and the velocities of the balls after the collision v₁ and v₂ are recorded.
The momentum before and after the collision is then calculated as follows:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
<h3>What is the statement of the law of conservation of momentum?</h3>
The law of the conservation of momentum states that the momentum before and after collision in a system of colliding bodies is conserved
The momentum of a body is calculated using the formula below:
Momentum = mass * velocity.
Hence, for the two billiard balls, the momentum before and after the collision is conserved.
Learn more about momentum at: brainly.com/question/1042017
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Answer:
4.68227 °C
Explanation:
= Mass of object = 500 kg
= Mass of water = 25 kg
c = Specific heat of water at 20°C = 4186 J/kg°C
h = Height from which the object falls = 100 m
g = Acceleration due to gravity = 9.8 m/s²
The potential energy and heat will balance each other
The temperature change in the water is 4.68227 °C
