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Romashka-Z-Leto [24]
3 years ago
14

3

Chemistry
1 answer:
solniwko [45]3 years ago
7 0

Answer:

A

Explanation:

With the given choices, A would be correct for this question.  But, both liquids and gases have particles that are far apart so that they can fill their containers.

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A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d
erica [24]

Answer:

1120 L.

Explanation:

Hello!

In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.

In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:

V_2=\frac{V_1*n_2}{n_1}

Thereby, we plug in to obtain:

V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L

Best regards!

4 0
3 years ago
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Neko [114]
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3 years ago
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If 85.0 L of helium at 29.0°C is compressed to 32.0 L at constant pressure, what is the new temperature?
Feliz [49]

Answer:

113.69°k

Explanation:

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              V1

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    T2=  113.69°K

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