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3 years ago

Choose the element described by the following electron configuration. 1s22s22p63s23p64s1

Chemistry

2 answers:

Sholpan [36]3 years ago

4 0

Answer:

Potassium

Explanation:

We are going to assume that this is an atom in it's ground state, not an ion.

Now let us count all the electrons

2 in the 1s orbital

2 in the 2s orbital

6 in the 2 p orbital

2 in the 3s orbital

6 in the 3p orbital

1 in the 4s orbital

Add them all up and we get 19. The element with 19 protons and hence 19 electrons in potassium

Jobisdone [24]3 years ago

3 0

Hey there.

By adding up all the "exponents," you'll get a number of 19. By looking at a periodic table, the element of such an atomic number is potassium or K.

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Chemical reactions forming ions _____.

Sergeu [11.5K]

The answer should be balance electrically

Chemical reactions that form ions should have a balanced charge. The example of the reaction is HCl. When forming ions, the equation should be:
HCl => $H^{+}$ + $Cl^{-}$
In this case, the hydrogen has one plus charge and chlorine has one negative charge. The resultant should be zero, so it's balanced.

4 0

3 years ago

A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati

Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.

$\text{calculating the initial HI}= \frac{mol}{V}$

$=\frac{9.3 \times 10 ^ -3}{2}$

$=0.00465 \ Mol$

$\text{Similarly}\ \ I_2 \ \ \text{follows} \ \ H_2 = 0 }$

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

$HI = 0.00465 - 2x\\\\ I_{2} \ eq = H_2 \ eq = 0 + x \\\\$

It is defined that:

$I_2 = 6.29 \times 10^{-4} \ M \\\\x = I_2 \\\\$

$HI \ eq= 0.00465 - 2x \\$

$=0.00465 -2 \times 6.29 \times 10^{-4} \\\\ = 0.00465 -\frac{25.16 }{10^4} \\\\ = 0.003392\ M$

Now, we calculate the position:

For the reaction $H 2(g) + I 2(g)\rightleftharpoons 2HI(g)$ , you can calculate the value of Kc at 1000 K.

data expression for Kc

$2HI \rightleftharpoons H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}$

$= \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386$

calculating the reverse reaction

$H_2(g) + I_2(g)\rightleftharpoons 2HI(g)$

$Kc = \frac{1}{Kc} \\\\$

$= \frac{1}{0.034386}\\ \\= 29.081\\$

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2 years ago

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ladessa [460]

What do you mean by unlock all of them? Please explain

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3 years ago

What type of reaction is represented in the following example?

Nikitich [7]

Answer:

endothermic

Explanation:

the negative sign of the heat indicates that heat is being drawn into the system, thus endothermic

3 0

3 years ago

Read 2 more answers

describe the law of conservation of energy and two examples of energy being transformed from one type to another.

VladimirAG [237]

Answer:

look in the explanation part

Explanation:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

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3 years ago