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Paha777 [63]
3 years ago
5

Choose the element described by the following electron configuration. 1s22s22p63s23p64s1

Chemistry
2 answers:
Sholpan [36]3 years ago
4 0

Answer:

Potassium

Explanation:

We are going to assume that this is an atom in it's ground state, not an ion.

Now let us count all the electrons

2 in the 1s orbital

2 in the 2s orbital

6 in the 2 p orbital

2 in the 3s orbital

6 in the 3p orbital

1 in the 4s orbital

Add them all up and we get 19. The element with 19 protons and hence 19 electrons in potassium

Jobisdone [24]3 years ago
3 0

Hey there.

By adding up all the "exponents," you'll get a number of 19. By looking at a periodic table, the element of such an atomic number is potassium or K.

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Chemical reactions forming ions _____.
Sergeu [11.5K]
The answer should be <span>balance electrically

</span><span>Chemical reactions that form ions should have a balanced charge. The example of the reaction is HCl. When forming ions, the equation should be:
HCl => </span>H^{+} + Cl^{-}
In this case, the hydrogen has one plus charge and chlorine has one negative charge. The resultant should be zero, so it's balanced.
4 0
3 years ago
A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati
Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.  

\text{calculating the initial HI}= \frac{mol}{V}

                                       =\frac{9.3 \times 10 ^ -3}{2}

                                      =0.00465 \ Mol

\text{Similarly}\ \  I_2 \ \  \text{follows} \ \  H_2 = 0 }

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

HI  = 0.00465 - 2x\\\\ I_{2}  \ eq = H_2 \ eq = 0 + x \\\\

It is defined that:

I_2 = 6.29 \times 10^{-4}  \ M \\\\x = I_2 \\\\

HI \ eq= 0.00465 - 2x \\

          =0.00465 -2 \times 6.29 \times 10^{-4} \\\\ =  0.00465 -\frac{25.16 }{10^4}  \\\\   = 0.003392\  M

Now, we calculate the position:  

For the reaction H 2(g) + I 2(g)\rightleftharpoons  2HI(g), you can calculate the value of Kc at 1000 K.  

data expression for Kc

2HI \rightleftharpoons  H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}

         = \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386

calculating the reverse reaction

H_2(g) + I_2(g)\rightleftharpoons  2HI(g)

Kc = \frac{1}{Kc} \\\\

     = \frac{1}{0.034386}\\ \\= 29.081\\

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3 years ago
What type of reaction is represented in the following example?
Nikitich [7]

Answer:

endothermic

Explanation:

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3 0
3 years ago
Read 2 more answers
describe the law of conservation of energy and two examples of energy being transformed from one type to another.
VladimirAG [237]

Answer:

look in the explanation part

Explanation:

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3 years ago
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