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Paha777 [63]
3 years ago
5

Choose the element described by the following electron configuration. 1s22s22p63s23p64s1

Chemistry
2 answers:
Sholpan [36]3 years ago
4 0

Answer:

Potassium

Explanation:

We are going to assume that this is an atom in it's ground state, not an ion.

Now let us count all the electrons

2 in the 1s orbital

2 in the 2s orbital

6 in the 2 p orbital

2 in the 3s orbital

6 in the 3p orbital

1 in the 4s orbital

Add them all up and we get 19. The element with 19 protons and hence 19 electrons in potassium

Jobisdone [24]3 years ago
3 0

Hey there.

By adding up all the "exponents," you'll get a number of 19. By looking at a periodic table, the element of such an atomic number is potassium or K.

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svlad2 [7]
Oxygen

Photosynthesis 

ATP (chemical energy)
6 0
3 years ago
A certain liquid sample has a volume of 14.7 mL and a mass of 22.8 grams. Calculate the density.
ira [324]
M = 22.8 g
V = 14.7 mL
ρ - ?

ρ = m/V
ρ = 22.8/14.7 = 1.55 g/mL

4 0
3 years ago
Percent Composition and Determining Empirical And Molecular Formulas
raketka [301]

Answer:

% comp. H = 2.8%, % comp. Cl = 97.2%

Explanation:

HCl mass = mass of H + mass of Cl

HCL mass = 1.00794 + 35.453 = 36.46094

% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)

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3 0
2 years ago
Select the correct answer.
almond37 [142]

Answer:

D. 5 moles

Explanation:

C3H8 + 5O2 → 4H2O + 3CO2

            5 mol                 3 mol

So, to make 3 mol CO2    5 mol O2 are needed.

3 0
3 years ago
zn (s) 2 hcl (aq) -----> zncl2 (aq) h2(g) if 520 ml of h2 is collected over water at 28oc and the atmospheric pressure is 1.0
nadya68 [22]

The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.

Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.

We recognise that

h * 2 = PT - P * h * 20 = 1atm - 0.037atm

= 0.963 atm

1 * h * 2 = Ph * 2V / R * T

= 0.963 atm x 0.520 L / 0.0821 L atm/

molK * 301

= 0.02 mol h2

= 0.02molZn

So 0.02 mol Zn x 65.39 g/mol

= 1.33 g Zn

Read more about zinc;

brainly.com/question/28880469

#SPJ4

3 0
1 year ago
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