A force of 15 N acts upon a 3 kg block. Calculate the acceleration of the object.

The motor of a four wheeler traveling along a muddy trail generates an average power of 7.48 104 W when moving at a constant spe

Radda [10]

Answer:

The tension in the tow rope pulling the log is 784.61 N

Explanation:

Given:

v = speed = 13 m/s

Pf = final power when the log is pulled = 8.5x10⁴W

Pi = average power = 7.48x10⁴W

The force required to move a car is equal to:

$F_{i} =\frac{P_{i} }{v} =\frac{7.48x10^{4} }{13} =5753.85 N$

$F_{f} =\frac{P_{f} }{v} =\frac{8.5x10^{4} }{13} =6538.46 N$

T = Ff - Fi = 6538.46 - 5753.85 = 784.61 N

7 0

4 years ago

Read 2 more answers

If a truck loses 5610 J of energy as it slows down due to an external force of 425 N, what distance will it have moved after the

lara31 [8.8K]

Answer:

13.2m

Explanation:

Step one:

given data

Energy= 5610J

Force F= 425N

Required

The distance traveled

Step two:

We know that work done is given as

WD= force* distance

so

5610=425*d

divide both sides by 425

d= 5610/425

d=13.2m

3 0

3 years ago

A 15-kg ball is tossed up into the air. The ball is 2 meters off the ground traveling 4 m/s. What is the potential energy? A. 29

Sladkaya [172]

Answer: 0j

Explanation:

At that point potential energy is zero and kinetic energy is maximum.. P. E=mgh=0

7 0

4 years ago

This is a form of energy representing the motion of the molecules which make up an object. A. Thermal Energy B. Kinetic Energy C

bija089 [108]

Answer:

Kinetic energy.

Explanation:

There are many kinds of energy. Some of them are kinetic energy, potential energy, thermal energy etc.
The energy that shows the motion of the object is called its kinetic energy.
Also, the sum of kinetic energy and the gravitational potential energy is called mechanical energy.
Out of the given options, kinetic energy is the form of energy that represents the motion of the molecules which make up an object.
Hence, the correct option is (B).

4 0

3 years ago

a baseball player is dashing toward home plate with a speed of 200 feet per hour. When he decides to hit the dirt. he slides for

Serggg [28]

To solve this problem we will use the kinematic formula for the final velocity.

$V_f_x = V_0_x + a_xt$

The final speed is 0 at the moment the player stops.

The time until it stops is 1.3 s

The initial speed is 200 feet / s Note (check the speed units in the problem statement, 200ft / s is very much and 200ft / h is very small)

Then, we clear the formula.

$a_x = \frac{(Vfx-V0x)}{t}\\ a_x = \frac{(0-200)}{1.3}\\ a_x = -153.5 ft / s ^ 2$

Because the player is slowing down, the acceleration goes in the opposite direction to the player's movement, and that is why it is negative.

To answer part b) we use the following formula.

$Vf ^ 2 = Vo ^ 2 + 2a * (x_2 - x_1)\\\\ (x_2 - x_1)= \frac{(V_f ^ 2-V_0 ^ 2)}{2a}\\\\ (x_2 - x_1)= \frac{(0-200 ^ 2)}{- 2 * 153.5}\\\\ (x_2 - x_1)= 130.29 feet$

8 0

3 years ago