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3 years ago

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Using Newton’s laws of motion, describe the motion of a roller coaster and analyze the forces acting on the roller coaster at di

fferent times of the ride (starting, going up hill, in a curve or in a loop).

1 answer:

Illusion [34]3 years ago

3 0

We can apply Newton's third law of motion in roller coaster.

Explanation:

If we are planning to make a roller coaster with elevations and turn then we need to apply newton’s law of motions, kinetic energy and potential energy.

Newton’s third law of motion says that “ for every action, there is an equal and opposite reaction”. Newton’s third law of motion applies between the tract and ride vehicles.

If we neglect the air resistance and friction, Roller coaster car will always experience two types of forces which are gravitational force and normal force. The normal force is acting perpendicular to the track and gravitational for is also acting downwards.

Whenever the tracts get moving the gravitational force is attracting roller coaster to downward. So this will get accelerates. In the majority of the roller coasters, the hill will decrease with height as the train moves along the tract.

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Which of the following months would be the darkest at the South Pole?

son4ous [18]

Answer:

December.

Explanation:

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3 years ago

Explain reaction of metals with the following with the help of chemical equations. i) with acids ii) with oxygen iii) with water

Amiraneli [1.4K]

i. When an acid reacts with metal, a salt and hydrogen are produced:

ii. When oxygen and metal react, metal oxide forms also known as rust

iii. metal and water produce hydrogen gas

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3 years ago

How would your experimental formula of magnesium chloride “MgClx” have been affected if

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The compound is used in medicine as a source of magnesium ions, which are essential for many cellular activities. Magnesium chloride has also been used as a cathartic and in alloys. To low

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3 years ago

Consider the reaction: 2 H2O (g)-->2 H2 (g) + O2 (g). ΔH=483.6 Kj/mol. If 2 moles of H2O (g) are converted H2(g) and O2(g) ag

denis-greek [22]

DE = dH - PdV

<span>2 H2O(g) → 2 H2(g) + O2(g) </span>

<span>You can see that there are 2 moles of gas in the reactants and 3 moles of gas in the products. </span>

<span>1 moles of ideal gas occupies the same volume as 1 mole of any other ideal gas under the same conditions of temp and pressure. </span>

<span>Since it is done under constant temp and pressure that means the volume change will be equal to the volume of 1 mole of gas </span>

<span>2 moles reacts to form 3 moles </span>

<span>The gas equation is </span>

<span>PV = nRT </span>
<span>P = pressure </span>
<span>V = volume (unknown) </span>
<span>n = moles (1) </span>
<span>R = gas constant = 8.314 J K^-1 mol^-1 </span>
<span>- the gas constant is different for different units of temp and pressure (see wikki link) in this case temp and pressure are constant, and we want to put the result in an equation that has Joules in it, so we select 8.314 JK^-1mol^-1) </span>
<span>T = temp in Kelvin (kelvin = deg C + 273.15 </span>
<span>So T = 403.15 K </span>

<span>Now, you can see that PV is on one side of the equation, and we are looking to put PdV in our dE equation. So we can say </span>

<span>dE = dH -dnRT (because PV = nRT) </span>

<span>Also, since the gas constant is in the unit of Joules, we need to convert dH to Joules </span>

<span>dH = 483.6 kJ/mol = 483600 Joules/mol </span>

<span>dE = 483600 J/mol - (1.0 mol x 8.314 J mol^-1K-1 x 403.15 K) </span>
<span>dE = 483600 J/mol - 3351.77 J </span>
<span>dE = 480248.23 J/mol </span>
<span>dE = 480.2 kJ/mol </span>

5 0

3 years ago

Read 2 more answers

The cost, C C, of producing x x Totally Cool Coolers is modeled by the equation C = 0.005 x 2 − 0.25 x + 12 C=0.005x2-0.25x+12 H

neonofarm [45]

Answer:

25 coolers are need to be produce and sell in order to minimize the cost.

Explanation:

$C = 0.005x^2-0.25x+12$ ..[1]

Differentiating the given expression with respect to dx.

$\frac{dC}{dx}=\frac{d(0.005x^2-0.25x+12)}{dx}$

$\frac{dC}{dx}=0.01x-0.25+0$

Putting , $\frac{dC}{dx}=0$

$0=0.01x-0.25+0$

$0.01x=0.25$

x = 25

Taking second derivative of expression [1]

$\frac{d^2C}{dx^2}=\frac{d(0.01x-0.25)}{dx}=0.01$

$\frac{d^2C}{dx^2}>0$ (minima)

25 coolers are need to be produce and sell in order to minimize the cost.

3 0

3 years ago