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Vlad1618 [11]
3 years ago
9

Using Newton’s laws of motion, describe the motion of a roller coaster and analyze the forces acting on the roller coaster at di

fferent times of the ride (starting, going up hill, in a curve or in a loop).
Chemistry
1 answer:
Illusion [34]3 years ago
3 0

We can apply Newton's third law of motion in roller coaster.

Explanation:

  • If we are planning to make a roller coaster with elevations and turn then we need to apply newton’s law of motions, kinetic energy and potential energy.
  • Newton’s third law of motion says that “ for every action, there is an equal and opposite reaction”. Newton’s third law of motion applies between the tract and ride vehicles.
  • If we neglect the air resistance and friction, Roller coaster car will always experience two types of forces which are gravitational force and normal force. The normal force is acting perpendicular to the track and gravitational for is also acting downwards.
  • Whenever the tracts get moving the gravitational force is attracting roller coaster to downward. So this will get accelerates. In the majority of the roller coasters, the hill will decrease with height as the train moves along the tract.

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Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100
vesna_86 [32]

<u>Answer:</u> The solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}

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The expression for solubility constant for this reaction will be:

K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2

We are given:

K_{sp}=2.5\times 10^{-33}

Putting values in above equation, we get:

2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L

Hence, the solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

6 0
3 years ago
Someone help me please
Roman55 [17]

Answer:

i know it bro

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mark me Brainliest

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