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Wittaler [7]
3 years ago
12

There are large spaces between gas molecules due to their weak

Chemistry
1 answer:
Eddi Din [679]3 years ago
8 0

Answer:

true

Explanation:

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Could somebody please give me an example of some physical properties for any substance?
KIM [24]

Answer:

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

Explanation:

6 0
2 years ago
The process that changes a solid directly into a gas is called sublimation. A solid that begins with a mass of 450 g will sublim
cluponka [151]
The mass is conserved, so it stays the same, 450g
5 0
2 years ago
Read 2 more answers
When a baseball bat hits a baseball, what happens to the energy?<br> completo ancur
professor190 [17]

Answer: the baseball bat transfor its energy in the ball.

Explanation: you hit it with one and find out and tell me what you think what happen.

3 0
2 years ago
At a certain temperature 3.24 moles of co2 gas at 2.15atm takes up a volume of 35.28 what is the temperature in celsius
andrew-mc [135]

Answer:

The temperature is 12.35 C.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

  • P= 2.15 atm
  • V= 35.28 L
  • n= 3.24 moles
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= ?

Replacing:

2.15 atm* 35.28 L= 3.24 moles* 0.082\frac{atm*L}{mol*K} * T

Solving:

T=\frac{2.15 atm* 35.28 L}{3.24 moles* 0.082\frac{atm*L}{mol*K}}

T=285.5 K= 12.35 C (being 273.15 K= 0 C)

<u><em>The temperature is 12.35 C.</em></u>

3 0
3 years ago
A 7.50-g sample of iron is heated in oxygen to form an iron oxide. if 10.71 g of the oxide is formed, what is its empirical form
Zielflug [23.3K]
Answer is: empirical formula is Fe₂O₃.
m(Fe) = 7,50 g.
m(iron oxide) = 10,71 g.
n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 7,50 g ÷ 55,85 g/mol = 0,134 mol.
m(O) = m(iron oxide) - m(Fe).
m(O) = 10,71 g - 7,50 g = 3,21 g.
n(O) = 3,21 g ÷ 16 g/mol = 0,20 mol.
n(Fe) : n(O) = 0,134 mol : 0,2 mol = 2 : 3.
3 0
3 years ago
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