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3 years ago

3. What measurement unit is used to measure molecules

Chemistry

2 answers:

lakkis [162]3 years ago

8 0

Answer: It is Mole.

Explanation:

Mole is the SI unit of measurement used to measure the number of things, usually atoms or molecules. One mole of something is equal to 6.02214078×1023 of same things (Avogadro's number).

zhannawk [14.2K]3 years ago

4 0

Mole is the SI unit of measurement used to measure

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2. Perception:

sineoko [7]

Answer:

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Someone's perception can be all of these things. the way one person sees something is different than the way someone standing right beside them sees it.

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4 years ago

Determine the number of moles of Mn and the number of moles of X in compound A. Clearly distinguish which is which in your calcu

KiRa [710]

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3 years ago

A. Draw 2,3-dichloro octane. b. Write the lewis structure for H20 molecule.

brilliants [131]

Answer:

a.draw 2,3 dicholoro octane

Explanation:

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3 years ago

Histamines are an important chemical in the body . what is their purpose in the immune system

pentagon [3]

Answer:

Histamine is a protein produced by mast cells in the body. It plays a very important role in the immune system of the body. Histamine is released in the body when affected by an allergen, e.g, pollen or animal dander. The immune system of the body will respond to such allergen by making more mucus in the nose by releasing histamine. There will be sneezing, itching, coughing and runny nose in response. This is a basic defense of the body's immune system to not enter any particle inside the body.

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4 years ago

If 43.7 g of iron is completely used to produce 62.5 g of iron (III) oxide, how many grams of oxygen are involved in the reactio

Kobotan [32]

Mass of Oxygen : 18.8 g

<h3>Further explanation</h3>

Reaction(balanced) :

4Fe + 3O₂ → 2Fe₂O₃

mass Fe = 43.7 g

mol Fe(MW= 55,845 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{43.7}{55.845}\\\\mol=0.783$

mol O₂ : mol Fe = 3 : 4, so mol O₂ :

$\tt \dfrac{3}{4}\times 0.783=0.5873$

Mass O₂(MW=32 g/mol) :

$\tt mass=mol\times MW\\\\mass=0.5873\times 32\\\\mass=18.7936~g\approx 18.8$

Or simply you can Conservation of mass, where the masses before and after the reaction are the same

mass reactants=mass products

mass iron+mass oxygen=mass iron (III) oxide

43.7 g + mass oxygen=62.5 g

mass oxygen = 62.5 - 43.7 = 18.8 g

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3 years ago