Don’t understand it. Please help

Chemistry

2 answers:

nikdorinn [45]3 years ago

7 0

Ok so basically you take an Ionic table and see if the charges for each compound cancel each other out. If they dont, add a subscript so the negative and positive charges cancel each other out. Then check of there is the same number of molecules on each side of the equation. i.e. nacl + cu-> cucl2 +na

On the product side there is 2 more chlorine than on the reactant side. so you would put a number in from of each compound until there is the same number of every molecule on all sides. i.e. 2nacl + cu -> 2na+ cucl2

frutty [35]3 years ago

5 0

some of those are on the periodic table and on the anion table

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mina [271]

Answer:

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Explanation:

Lava to Rock is incorrect because its "Freezing" The Lava

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3 years ago

What mass of solid that has a molar mass 89.0 g/mol should be added to 100.0 g of benzene to raise the boiling point of benzene

taurus [48]

On the basis of given data:

Mass of solvent (benzene) = 100 gm or 0.1 Kg

Molar mass of solute (solid) = 89 g/mol

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The boiling point elevation constant k = 2.53 C.kg/mol

There is a need to determine the mass of the solid to be added, the elevation in boiling point is proportional to the m (molality) of the solute;

ΔTb = k.m

Here, m that is molality = moles of solute/kg of solvent

Therefore,

ΔTb = k (benzene) × moles of solid/kg of benzene

2.42 = 2.53 × moles of solid/0.1

moles of solid = 0.0956 moles

The molar mass of solid = 89 g/mol

Thus, the mass of solid = 0.0956 moles × 89 g/mol

= 8.508 g

Thus, the mass of solid to be added is 8.508 g.

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3 years ago

Knowing the molarity of a solution is more meaningful than knowing whether a solution is dilute or concentrated. explain.

ser-zykov [4K]

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It is more important and meaningful to know the molarity rather than if the solution is dilute or concentrated because molarity gives the QUANTITATIVE approach of knowing the concentration while the second one only gives us the QUALITATIVE description of the solution. Hence, we are able to calculate for other unknown parameters if we have the molarity known.

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kolezko [41]

Answer:

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