All categories

3 years ago

Don’t understand it. Please help

Chemistry

2 answers:

nikdorinn [45]3 years ago

7 0

Ok so basically you take an Ionic table and see if the charges for each compound cancel each other out. If they dont, add a subscript so the negative and positive charges cancel each other out. Then check of there is the same number of molecules on each side of the equation. i.e. nacl + cu-> cucl2 +na

On the product side there is 2 more chlorine than on the reactant side. so you would put a number in from of each compound until there is the same number of every molecule on all sides. i.e. 2nacl + cu -> 2na+ cucl2

frutty [35]3 years ago

5 0

some of those are on the periodic table and on the anion table

You might be interested in

How does the electric force between two charged particles change if the

Anuta_ua [19.1K]

C. It is decreased by a factor of 3.

3 0

3 years ago

Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−

Lady bird [3.3K]

Answer : The molarity after a reaction time of 5.00 days is, 0.109 M

Explanation :

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $9.7\times 10^{-6}M^{-1}s^{-1}$

t = time taken = 5.00 days

[A] = concentration of substance after time 't' = ?

$[A]_o$ = Initial concentration = 0.110 M

Now put all the given values in above equation, we get:

$9.7\times 10^{-6}=\frac{1}{5.00}\left (\frac{1}{[A]}-\frac{1}{(0.110)}\right)$

$[A]=0.109M$

Hence, the molarity after a reaction time of 5.00 days is, 0.109 M

8 0

3 years ago

What reaction is depicted by the given equation: au3 3e− au

mrs_skeptik [129]

This is a reduction half-reaction. Initially, gold exists as $Au^{3+}$ , and after the reaction, it has been converted to elemental gold. To make this possible, three electrons must be added to <span> $Au^{3+}$ . This fits within the definition of reduction reactions, where the reactant gains electrons in the reaction.</span>

3 0

3 years ago

How do geologists use seismic waves to locate an earthquakes epicenter

GREYUIT [131]

The waves detect magnetic waves and the disturbances in the to locate where a earth quake will or may hit

6 0

3 years ago

Draw structures from the following names, and determine which compounds are optically active:(c) 1,2-dibromo-2-methylbutane

dolphi86 [110]

The given compound 1,2-dibromo-2-methylbutane is an optically active compound .

Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has chiral center.

Here , the chiral carbon is attached to the 4 distinct groups such as : methyl , ethyl , bromine , bromomethane .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

brainly.com/question/9522537

#SPJ4

8 0

1 year ago