Answer:
The number of moles of CH₄ that will remain is 7.5 moles
Explanation:
Complete combustion reaction of oxygen and methane is given as;
CH₄ + 2O₂ → CO₂ + 2H₂O
comparing the number of moles of methane and oxygen in the reaction above, the amount of methane used in the reaction is calculated as follows;
2 moles of O₂ -----------> 1 mole of CH₄
7 moles of O₂ ------------> x moles of CH₄
x = 7 / 2
x = 3.5 moles of CH₄
Total moles of CH₄ in the reactor = 11.0 moles
The number of moles that will remain = 11.0 moles - 3.5 moles
The number of moles that will remain = 7.5 moles
Therefore, the number of moles of CH₄ that will remain is 7.5 moles
false all element when they are combined eachother thier valance number will change
the combination of oxygen and aluminum gives us Al2O3 see even the numbers are changing thank you if you have a comment you can write
Answer:
2.05882 g/cm3
Explanation:
the formula p=m/V, or density (p) is equal to mass (m) divided by volume (V)
D.
because that can only be the answer
