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3 years ago

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A hungry 173173 kg lion running northward at 82.782.7 km/hr attacks and holds onto a 36.236.2 kg Thomson's gazelle running eastw

ard at 57.457.4 km/hr. Find the final speed of the lion–gazelle system immediately after the attack.

1 answer:

Galina-37 [17]3 years ago

8 0

Answer:

the final speed after attack is 69.09 km/h

Explanation:

lion weight = 173 kg

running northward at 82.7 km/hr

weight of gazelle = 36.2 kg

running eastward at 57.4 km/hr

using momentum conservation along north direction

(173) × (82.7) = (173 + 36.2 ) × vₙ

vₙ = 68.38 km/h

using momentum conservation along east direction

36.2 × 57.4 = (173 + 36.2 ) × vₓ

vₓ = 9.93 km/h

$v = \sqrt{v^2_n+v^2_x} \\v = \sqrt{68.38^2+9.93^2}\\v=69.09 km/h$

hence the final speed after attack is 69.09 km/h

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