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Levart [38]
3 years ago
13

A man is running on the straight road with the uniform velocity of 3 metre per second calculate the acceleration for produced hi

m​
Physics
1 answer:
sp2606 [1]3 years ago
6 0

Theoritically

the body moving with uniform velocity has acceleration zero.

Mathmatically,

u=3m/s

v=3m/s (since body is moving with uniform velocity)

a= v-u/t

3-3/t

0/t

0m/s.s

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A 3.8 kg ball is rolling eastward across a horizontal,
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Answer:

12

Explanation:

8 0
3 years ago
Describe the basis concept of the atwood’s machine
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Answer:The Atwood Machine is a device that demonstrates the basic principles of acceleration and dynamics. You'll mostly see Atwood machines in Physics laboratories and classrooms. It consists of two objects with different masses that hang vertically from a frictionless pulley that has a very small, negligible mass.

Explanation:

8 0
3 years ago
A baseball approaches home plate at a speed of 44.0 m/s, moving horizontally just before being hit by a bat. The batter hits a p
Luda [366]

Explanation:

It is given that,

Speed of the baseball, u = 44 m/s

Speed of the baseball, v = 53 m/s

Mass of the ball, m = 145 g = 0.145 kg

Time of contact between the ball and the bat, t = 2.2 ms = 0.0022 s

F=ma

F=\dfrac{mv}{t}

F_1=\dfrac{0.145\ kg\times 44\ m/s}{0.0022\ s}

F₁ = 2900 N...........(1)

F=ma

F=\dfrac{mv}{t}

F_2=\dfrac{0.145\ kg\times 53\ m/s}{0.0022\ s}

F₂ = 3493.18 N.........(2)

In average vector form force is given by :

F=F_1+F_2

F=(2900i+(-3493.18)\ N

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6 0
3 years ago
A traditional set of cycling rollers has two identical, parallel cylinders in the rear of the device that the rear tire of the b
mars1129 [50]

Answer:

ω2  =  216.47 rad/s

Explanation:

given data

radius r1 =  460 mm

radius r2 = 46 mm

ω =  32k rad/s

solution

we know here that power generated by roller that  is

power = T. ω    ..............1

power = F × r × ω

and this force of roller on cylinder is equal and opposite force apply by roller

so power transfer equal in every cylinder so

( F × r1 × ω1)  ÷ 2 = (  F × r2 × ω2 )  ÷  2    ................2

so

ω2  =  \frac{460\times 32}{34\times 2}

ω2  =  216.47

8 0
3 years ago
Electron grops could be considered which of the following
Maurinko [17]

Answer:

Electron groups could be considered as  Lone pair electrons and bonded pairs of electrons.

Answer: Option D & B

Explanation:

The two or more electrons can be bonded by single bond, double bond, covalent bond of electrons can simply be lone pair of electrons. Unshared pair of electrons are generally termed as lone pair of electrons in an atom which are generally present in the outermost shell of atoms. Hence electron groups can be determined by bonded pairs and lone pairs of electrons.

I got this from another brainly user

5 0
2 years ago
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