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klasskru [66]
3 years ago
10

**

Physics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

The object will have an upward acceleration

Explanation:

Let's consider the forces applied on the box. We have only two forces:

- The applied force of push, F_p, downward

- The force of gravity, W, (also known as weight of the object), downward

Therefore, the net force on the box is:

F_{net}=F_p -W

Here, we know that force applied is equal or greater than the weight, so

F_p \geq W

And therefore the net force is greater than zero:

F_{net}\geq 0 (1)

According to Newton's second law of motion, the net force on the box is equal to the product between its mass and its acceleration:

F_{net}=ma

where

m is the mass of the box

a is its acceleration

Given (1), this means that

a\geq 0

Therefore, the box will have an upward acceleration.

In this case force example we have:

F_p = 100 N\\W = 40 N

So the mass of the box is

m=\frac{W}{g}=\frac{40}{10}=4 kg

So the net force is

F_{net}=F_p-W=100-40=60 N

And the acceleration is

a=\frac{F_{net}}{m}=\frac{60}{4}=15 m/s^2

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a man stands in a lift going downward with uniform velocity. he experiences a loss of weight at the start but not when lift is i
AnnyKZ [126]

Answer:

It is explained in the explanation section

Explanation:

When the lift starts going downwards, it will start accelerating downwards. After a while, it will start moving with a constant velocity.

Constant velocity means that acceleration is zero and so the man will not feel any weight loss.

Now, Once the lift achieves constant velocity the acceleration is zero hence he will not experience any weight loss.

However, when the lift is in uniform motion, the lift and the man will fall down with an acceleration(a) that is less than that due to gravity(g) . Thus, the man will feel an apparent weight F which is not equal to zero.

6 0
3 years ago
Consider the minute hand on a clock. (a) Compute the frequency of its motion in cycles per second. State your answer to three si
kicyunya [14]

Answer:

(a)0.0002778

(b)1.16\times10^{-5}

Explanation:

(a) The minute hand has a period of 60 minutes ( or 60 * 60 = 3600 seconds) for 1 circle. Its frequency per second would be

1 / 3600 = 0.0002778

(b) The hour hand has a period of 24 hours ( or 24*60 * 60 = 86400

seconds) for 1 circle. Its frequency per second would be

1 / 86400 = 1.16\times10^{-5}

5 0
2 years ago
At constant volume, the heat of combustion of a particular compound is − 3550.0 kJ / mol. When 1.075 g of this compound ( molar
swat32

Answer:

C=1,25\cdot 10^{5} kJ/^{\circ}C

Explanation:

First of all let's define the specific molar heat capacity.

C = \frac{-Q}{n\cdot \Delta T} (1)

Where:

Q is the released heat by the system

n is the number of moles

ΔT is the difference of temperature of the system  

Now, we can find n with the molar mass (M) the mass of the compound (m).

n=\frac{m}{M}=6.95\cdot 10^{-3} moles      

Using (1) we have:

C=\frac{-3550}{6.95\cdot 10^{-3} 4.073}

C=1,25\cdot 10^{5} kJ/^{\circ}C

I hope it helps!

6 0
3 years ago
5. A cart with one fan on It blowing to the left and carrying one block produces the x vs t graph shown If this car were carryin
kumpel [21]

Answer:

Graph C

Explanation:

With the same force and more mass, the position in time will still be parabolic

i.e.  x = ½at², but the rate of acceleration will be lower so the position curve will be broader.

5 0
3 years ago
If you need 40.0 Nm of torque in order to loosen a nut on a wn
KonstantinChe [14]

Answer:

0.301 m

Explanation:

Torque = Force × Radius

τ = Fr

40.0 Nm = 133 N × r

r = 0.301 m

The mechanic must apply the force 0.301 m from the nut.

6 0
2 years ago
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