All categories

2 years ago

A 0.15-m straight wire moves with a constant velocity of 7.0 m/s perpendicularly

Physics

1 answer:

lana66690 [7]2 years ago

8 0

Answer: force is 0.42 N

Explanation: F = l·v·B

You might be interested in

A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of

Katen [24]

Answer:

S = V t where S is the horizontal distance traveled

1/2 g t^2 = H where H is the vertical distance traveled

t^2 = 2 H / g

V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations

tan theta = H / S

V^2 = S g / (2 tan theta)

Using S = L cos theta

V^2 = L g cos theta / (2 tan theta)

Giving V in terms of L and theta

7 0

2 years ago

A flying squirrel has a mass of 0. 765 kg. He jumps off the tree and hits the ground with 125 joules of energy. Determine how hi

uranmaximum [27]

Answer:

Height, h = 16.67 m

Explanation:

We have,

Mass of a squirrel is 0.765 kg.

He jumps off the tree and hits the ground with 125 joules of energy.

It is required to find the height up on the tree the squirrel was when it jumped.

The energy possessed by the squirrel is called its gravitational potential energy. It can be given by :

$E=mgh$

h is height up on the tree the squirrel was when it jumped

$h=\dfrac{E}{mg}\\\\h=\dfrac{125\ J}{0.765\ kg\times 9.8\ m/s^2}\\\\h=16.67\ m$

So, the squirrel will go to a height of 16.67 m.

6 0

2 years ago

An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 581 km from the center of asteroid

mariarad [96]

Answer:

0.05806

Explanation:

$m_x$ = Mass of asteroid x

$m_y$ = Mass of asteroid y

$r_x$ = Distance from asteroid x = 140 km

$r_y$ = Distance from asteroid y = 581 km

m = Mass of asteroid

Force of gravity between asteroid x and the astronaut

$F_1=\frac{Gm_xm}{r_x^2}\\\Rightarrow F_1=\frac{Gm_xm}{140^2}$

Force of gravity between asteroid x and the astronaut

$F_2=\frac{Gm_ym}{r_y^2}\\\Rightarrow F_2=\frac{Gm_ym}{581^2}$

Here these two forces are equal as they are in equilibrium

$\frac{Gm_xm}{140^2}=\frac{Gm_ym}{581^2}\\\Rightarrow \frac{m_x}{140^2}=\frac{m_y}{581^2}\\\Rightarrow \frac{m_x}{m_y}=\frac{140^2}{581^2}\\\Rightarrow \frac{m_x}{m_y}=0.05806$

The ratio of the masses of the asteroid is 0.05806

4 0

2 years ago

HELPP!

Marizza181 [45]

5000.700 is the answer good luck

4 0

2 years ago

Which is true of the buoyant force?

crimeas [40]

Buoyant force A. acts in the upward direction.

If the Buoyant force is greater than the gravitational force (as seen in ducks), they will stay floated

If the Buoyant force is less than the gravitational force (for example, a leaking ship) the ship would sink.

hope this helps

5 0

3 years ago