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Monica [59]
3 years ago
6

Astronauts increased in height by an average of approximately 40 mm (about an inch and a half) during the Apollo-Soyuz missions,

due to the absence of gravity compressing their spines during their time in space. Does something similar happen here on Earth
Physics
1 answer:
swat323 years ago
5 0

Answer:

<em>Yes. Something similar occurs here on Earth.</em>

Explanation:

Gravity tends to pull objects perpendicularly to the ground. In space, the absence of this force means there is no compression on the spine due to gravity trying to pull it down. This means that astronauts undergo an increase in height in space.

Here on Earth, we experience gravity pull on our spine during the day. At night when we sleep, we lie down with our spine parallel to the ground, which means that our spine is no longer under compression from gravity force. The result is that we are a few centimetres taller in the morning when we wake up, than we are before going to bed at night. The increase is not much pronounced here on Earth because there is a repeated cycle of compression and decompression of our spine due to gravity, unlike when compared to that of astronauts that spend long duration in space, all the while without gravity forces on their spine

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A 600kg car is at rest, and then it accelerates to 5 m/s.
uranmaximum [27]

Answer:

1. 0 J

2. 7500 J

3. 7500 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Final velocity (v₂) of car = 5 m/s

Original kinetic energy (KE₁) =?

Final kinetic energy (KE₂) =?

Work used =?

1. Determination of the original kinetic energy.

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Original kinetic energy (KE₁) =?

KE₁ = ½mv₁²

KE₁ = ½ × 600 × 0²

KE₁ = 0 J

Thus, the original kinetic energy of the car is 0 J.

2. Determination of the final kinetic energy.

Mass (m) of car = 600 Kg

Final velocity (v₂) of car = 5 m/s

Final kinetic energy (KE₂) =?

KE₂ = ½mv₂²

KE₂ = ½ × 600 × 5²

KE₂ = 300 × 25

KE₂ = 7500 J

Thus, the final kinetic energy of the car is 7500 J

3. Determination of the work used.

Original kinetic energy (KE₁) = 0

Final kinetic energy (KE₂) = 7500 J

Work used =?

Work used = KE₂ – KE₁

Work used = 7500 – 0

Work used = 7500 J

6 0
2 years ago
A wire of length L is wound into a square coil with 167 turns and used in a generator that operates at 60.0 Hz and 120 V rms val
Mrac [35]

Answer:

171.43m

Explanation:

First, define emf( electromotive force )-is the unit electric charge imparted by an energy source. In this case the generator.

The peak emf is:

E_p_e_a_k=\sqrt2(E_m_a_x)=\sqrt(2\times 120V)=170V

Substituting w=2\pi f and the value for peaf E gives:

Total length=4\sqrt {\frac{NE_p_e_a_k}{Bw}=4\sqrt{\frac{167\times 170}{0.041T\times 2pi \times 60.0Hz}

=171.43m

Hence, wire's length is 171.43m

8 0
3 years ago
What elements have similar behavior?
ki77a [65]

The elements which have similar behavior are Barium, strontium and beryllium.

7 0
3 years ago
What is the speed of a bird of mass 8kg which has kinetic energy of 8836J?
Kay [80]

Answer:

For the bird moving in a straight line, the kinetic energy is one-half the product of the mass and the square of the speed: Ek=12mu2.

4 0
3 years ago
Search about non-ohmic devices in 3 pages​
Tomtit [17]

Answer:

electronic diode,

Explanation:

Non-ohmic conductors are materials that do not obey ohm's law and they are electronic diode, transistors, tungsten, thermistors and vacuum tube etc.

7 0
3 years ago
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