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Studentka2010 [4]
3 years ago
9

The bending of light as it passes into a transparent material of different optical intensity is known as A. conversion. B. aberr

ation. C. reflection. D. refraction
Physics
1 answer:
stiks02 [169]3 years ago
6 0

Answer:

<em>D. refraction</em>

Explanation:

Refraction: Refraction is change in direction of light rays. Refraction occurs whenever light rays travels from a transparent medium to another transparent medium of different density. The abrupt change in direction at the surface of the surface of the two media is referred to as <em>refraction</em><em>.</em>

<em>Refraction occurs when light travels from air to glass or from air to liquid.</em>

<em>Laws Of Refraction:</em>

(i) The incident ray, the refracted ray and the normal, all at the point of incident lies in the same plane.

(ii) The ratio of the sine of the angle of incident to the sine of the angle of refraction is a constant for a given pair of media.

<em>Thus the right option is D. refraction</em>

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7 0
3 years ago
What is the strategy you use to solve word problems in physics?
Inga [223]

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3 0
2 years ago
A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º. What is the coefficient of
Alex_Xolod [135]

Given :

A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.

To Find :

The coefficient of static friction between the box and the plane.

Solution :

Vertical component of force :

mg\ sin\ \theta =  120\times 10 \times sin\ 47^\circ{}=877.62 \ N

Horizontal component of force(Normal reaction) :

mg\ cos\ \theta =  120\times 10 \times cos\ 47^\circ{}=818.40 \ N

Since, box is on the verge of slipping :

mg\ sin\ \theta= \mu(mg \ cos\ \theta)\\\\\mu = tan \ \theta\\\\\mu = tan\ 47^o\\\\\mu = 1.07

Therefore, the coefficient of static friction between the box and the plane is 1.07.

Hence, this is the required solution.

7 0
3 years ago
Frequency<br> In excercising
Gennadij [26K]

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3 0
3 years ago
Which electromagnetic waves have the shortest wavelengths and highest frequencies?
Usimov [2.4K]

Answer: Gamma rays

Explanation: The given waves belong to the electromagnetic spectrum which consists of different electromagnetic radiations arranged in terms of increasing wavelengths or decreasing frequencies.

E= h\times \nu

\nu=\frac{c}{\lambda}

Thus E=\frac{h\times c}{\lambda}

E= energy

\nu= frequency

c = speed of light

\lambda = wavelength

Thus frequency and wavelength are inversely related. The waves having high energies ave high frequencies and have shorter wavelengths.

Thus gamma rays having highest energy have highest frequency and shortest wavelength.


3 0
3 years ago
Read 2 more answers
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